Question

我的代码如下：

a=zeros(5,1);
f=zeros(5,5);
for i=1:5
a(i,1)=5;
 f(:,i)=a;
end

我希望每个循环的结果都是矩阵f的每一列。我的意思是f = [a（1）a（2）a（3）a（4）a（5）]其中a（i）来自for循环中的每个循环。但结果是：

 5     5     5     5     5
 0     5     5     5     5
 0     0     5     5     5
 0     0     0     5     5
 0     0     0     0     5

我是matlab的新手。如果你告诉我哪里错了，我们将不胜感激。

Answer 1

这样做

a=zeros(5,1);
f=zeros(5,5);
a(:,1)=5;
f(1,:)=transpose(a);

Answer 2

I see that in line 4 you have a(:,1)=5. Since it is on a loop the value of a continues to expand so that you first have a(1)=5, a(2)= 5 5, a(3)= 5 5 5, etc. What you want to do is specify what specific value of a you want in your matrix f. You can do this by:

a=zeros(5,1);

f=zeros(5);

for i=1:5

a(i,1)=5;

f(i,i)=a(i,1); end

disp(f)

如何在矩阵的每一列中放置for循环的结果？

2 个答案: