$(document).ready(function(){
$("#addpc").submit(function(){
var formdata=$("#addpc").serialize();
$.ajax({
url:"asset_management/addcomp",
type:"POST",
data: formdata,
async: true,
}).done(function( formdata ) {
$('#info').html(formdata);
$("#addpc")[0].reset();
viewdata();
});
return false;
});
});
对于上面的代码,如果我每次k改变时将qk(k)设置为新矩阵。无论如何要做到这一点?我尝试声明为for (k = 0; k < 5; k++)
{
Xnew[k + 1] = Xold[k] + (T * MPCV[k]) * Math.Cos(Aold[k]);
Ynew[k + 1] = Yold[k] + (T * MPCV[k]) * Math.Sin(Aold[k]);
Anew[k + 1] = Aold[k] + (T * MPCW[k]);
Console.WriteLine("\nXnew = {0}", Xnew[k + 1]);
Console.WriteLine("Ynew = {0}", Ynew[k + 1]);
Console.WriteLine("Tnew = {0}", Anew[k + 1]);
double[,] qk = { { Xnew[k + 1] }, { Ynew[k + 1] }, { Anew[k + 1] } };
Console.WriteLine("the element is {0}", Xnew[k + 1]);
Console.WriteLine("the element is {0}", Ynew[k + 1]);
Console.WriteLine("the element is {0}", Anew[k + 1]);
}
,但它没有用。
一个例子是当我的k增加时,我的Xnew,ynew和anew的值也将随k变化。因此,我会声明q(k)当k增加时k将增加并且重新存储值xnew ynew。