我正在使用Python Imaging Library的ImageDraw.line()绘制一堆行,但是它们看起来很可怕,因为我找不到对其进行反别名的方法。如何在PIL中消除别名线?如果PIL无法做到,那么还有另一个Python图像处理库吗?
答案 0 :(得分:11)
这是一个非常快速被黑客攻击的功能,用于绘制与PIL的反锯齿线,我在谷歌搜索相同的问题后写的,看到这篇文章并且未能安装aggdraw并且在紧迫的截止日期之前。这是Xiaolin Wu的线算法的实现。我希望它可以帮助任何人搜索同样的东西!!
:)
"""Library to draw an antialiased line."""
# http://stackoverflow.com/questions/3122049/drawing-an-anti-aliased-line-with-thepython-imaging-library
# https://en.wikipedia.org/wiki/Xiaolin_Wu%27s_line_algorithm
import math
def plot(draw, img, x, y, c, col, steep, dash_interval):
"""Draws an antiliased pixel on a line."""
if steep:
x, y = y, x
if x < img.size[0] and y < img.size[1] and x >= 0 and y >= 0:
c = c * (float(col[3]) / 255.0)
p = img.getpixel((x, y))
x = int(x)
y = int(y)
if dash_interval:
d = dash_interval - 1
if (x / dash_interval) % d == 0 and (y / dash_interval) % d == 0:
return
draw.point((x, y), fill=(
int((p[0] * (1 - c)) + col[0] * c),
int((p[1] * (1 - c)) + col[1] * c),
int((p[2] * (1 - c)) + col[2] * c), 255))
def iround(x):
"""Rounds x to the nearest integer."""
return ipart(x + 0.5)
def ipart(x):
"""Floors x."""
return math.floor(x)
def fpart(x):
"""Returns the fractional part of x."""
return x - math.floor(x)
def rfpart(x):
"""Returns the 1 minus the fractional part of x."""
return 1 - fpart(x)
def draw_line_antialiased(draw, img, x1, y1, x2, y2, col, dash_interval=None):
"""Draw an antialised line in the PIL ImageDraw.
Implements the Xialon Wu antialiasing algorithm.
col - color
"""
dx = x2 - x1
if not dx:
draw.line((x1, y1, x2, y2), fill=col, width=1)
return
dy = y2 - y1
steep = abs(dx) < abs(dy)
if steep:
x1, y1 = y1, x1
x2, y2 = y2, x2
dx, dy = dy, dx
if x2 < x1:
x1, x2 = x2, x1
y1, y2 = y2, y1
gradient = float(dy) / float(dx)
# handle first endpoint
xend = round(x1)
yend = y1 + gradient * (xend - x1)
xgap = rfpart(x1 + 0.5)
xpxl1 = xend # this will be used in the main loop
ypxl1 = ipart(yend)
plot(draw, img, xpxl1, ypxl1, rfpart(yend) * xgap, col, steep,
dash_interval)
plot(draw, img, xpxl1, ypxl1 + 1, fpart(yend) * xgap, col, steep,
dash_interval)
intery = yend + gradient # first y-intersection for the main loop
# handle second endpoint
xend = round(x2)
yend = y2 + gradient * (xend - x2)
xgap = fpart(x2 + 0.5)
xpxl2 = xend # this will be used in the main loop
ypxl2 = ipart(yend)
plot(draw, img, xpxl2, ypxl2, rfpart(yend) * xgap, col, steep,
dash_interval)
plot(draw, img, xpxl2, ypxl2 + 1, fpart(yend) * xgap, col, steep,
dash_interval)
# main loop
for x in range(int(xpxl1 + 1), int(xpxl2)):
plot(draw, img, x, ipart(intery), rfpart(intery), col, steep,
dash_interval)
plot(draw, img, x, ipart(intery) + 1, fpart(intery), col, steep,
dash_interval)
intery = intery + gradient
答案 1 :(得分:3)
aggdraw提供比PIL更好的绘图。
答案 2 :(得分:2)
我有类似的问题,我的线条粗糙的边缘改变方向。我从IOS中绘制了如何绘制线条的线索,并想出了这段代码。它在线的末端放置圆形线帽,真正清理了一些东西。不完全抗锯齿,但对PIL来说是全新的,并且很难找到我认为我会分享的答案。需要一些调整,可能有更好的方法,但做我需要的:))
from PIL import Image
import ImageDraw
class Point:
def __init__(self, x, y):
self.x = x
self.y = y
class DrawLines:
def draw(self, points, color, imageName):
img = Image.new("RGBA", [1440,1080], (255,255,255,0))
draw = ImageDraw.Draw(img)
linePoints = []
for point in points:
draw.ellipse((point.x-7, point.y-7, point.x+7, point.y+7), fill=color)
linePoints.append(point.x)
linePoints.append(point.y)
draw.line(linePoints, fill=color, width=14)
img.save(imageName)
p1 = Point(100,200)
p2 = Point(190,250)
points = [p1,p2]
red = (255,0,0)
drawLines = DrawLines()
drawLines.draw(points, red, "C:\\test.png")