通过迭代python

时间:2015-06-23 06:09:39

标签: python xml-parsing elementtree

我已经检查了这个link,但它并没有解决我的问题。

我有2个名单:

a = [['txt','stxt','pi','min','max'],['txt1','stxt1','pi1','min1','max1']]
b = [[0.45,1.23],[[0.75,1.53]]

 for l1 in a:
     for l2 in b:
         root = ET.Element("Class ",name = l1[0])
         doc = ET.SubElement(root, "subclass" , name = l1[1])
         ET.SubElement(doc, l1[4], min = str(l2 [0]),max = str(l2 [1]))
         tree = ET.ElementTree(root)
         tree.write(FilePath)

最后一条记录将覆盖所有以前的记录。所以,如果我想将所有记录写入xml文件?我怎么能用python编程做到这一点。我还希望每个记录都以新行保存到xml文件中,但不能完全打印。

输出我需要添加到xml:

<Class  name="txt"><subclass name="stxt"><pi max="1.23" min="0.45" /></subclass></Class >
<Class  name="txt1"><subclass name="stxt1"><pi1 max1="1.53" min1="0.75" /></subclass></Class >

但我得到的只是xml中的一条记录:

<Class  name="txt1"><subclass name="stxt1"><pi1 max1="0.1077" min1="-0.0785" /></subclass></Class >

1 个答案:

答案 0 :(得分:0)

您每次都在写同一个文件。您需要为每个输入创建新文件,而两个for循环将使4个文件具有不需要的组合。相反,zip是你需要的

a = [['txt','stxt','pi','min','max'],['txt1','stxt1','pi1','min1','max1']]
b = [[0.45,1.23],[0.75,1.53]]
from xml.etree import ElementTree as ET
root =  ET.Element("xml")
for l1 in zip(a,b):
        sroot_root = ET.Element("Class ",name = l1[0][0])
        doc = ET.SubElement(sroot_root, "subclass" , name = l1[0][1])
        ET.SubElement(doc, l1[0][4], min = str(l1[1][0]),max = str(l1[1][1]))
        root.append(sroot_root)


tree = ET.ElementTree(root)
tree.write("test.xml")

输出:

文件名: test.xml

<xml><Class  name="txt"><subclass name="stxt"><max max="1.23" min="0.45" /></subclass></Class ><Class  name="txt1"><subclass name="stxt1"><max1 max="1.53" min="0.75" /></subclass></Class ></xml>