Question

我有一本这样的字典：

{
   "month": ["January", "February", "March"],
   "volume": [1,2,3],
   "target": [6,8,5]
}

我想遍历每个键和值，以便创建如下列表：

["month: January, volume: 1, target: 6", "month: February, volume: 2, target: 8", "month: March, volume: 3, target: 5"]

如何逐个循环遍历每个键值，直到到达最后一个列表的数组值的末尾？每个密钥的所有列表的长度都相同。

Answer 1

d = {
   "month": ["January", "February", "March"],
   "volume": [1,2,3],
   "target": [6,8,5]
}

keys = tuple(d)  # ('month', 'volume', 'target')
values = tuple(zip(*d.values()))  # (('January', 1, 6), ('February', 2, 8), ('March', 3, 5))

your_list = [
    ', '.join(
        f'{keys[i]}: {value[i]}' 
        for i in range(len(keys))  # range(3) in this case
    ) 
    for value in values
]

print(your_list)

输出：

['month: January, volume: 1, target: 6',
 'month: February, volume: 2, target: 8',
 'month: March, volume: 3, target: 5']

Answer 2

假设所有值的长度相同：

di = {
    "month": ["January", "February", "March"],
    "volume": [1,2,3],
    "target": [6,8,5],
}
sample_length = len(list(di.values())[0])
final_list = []
for j in range(sample_length):
    list_item = []
    for key, val in di.items():
        list_item.append('{}: {}'.format(key, val[j]))
    final_list.append(', '.join(list_item))
print(final_list)

输出：

['month: January, volume: 1, target: 6', 'month: February, volume: 2, target: 8', 'month: March, volume: 3, target: 5']

Answer 3

使用此示例：

di = {
   "month": ["January", "February", "March"],
   "volume": [1,2,3],
   "target": [6,8,5],
}

一个想法就是将其转换为列表

li = [ [k + ": " +str(v) for v in v_list] for k,v_list in test_dict.items()]

然后使用zip进行连接

[ ', '.join(l) for l in zip(*li) ]

这是结果：

['month: January, volume: 1, target: 6',
 'month: February, volume: 2, target: 8',
 'month: March, volume: 3, target: 5']

遍历字典中的列表

3 个答案: