我试图在java中将两个.xlsx文件合并到一起。但我在某种程度上得到了行
的NullPointerException if (cell.getSheet().getWorkbook() == mcell.getSheet()
.getWorkbook()) {
}
任何想法可能导致此错误?当我在合并其他两个文件之前尝试时,我的代码工作得很好,但现在我更改了文件,现在得到NullPointerException。我尝试合并的新文件有2张。我只需要合并它们的第一页。
这是我的代码:
public static void main(String[] args) {
try {
FileInputStream excellFile1 = new FileInputStream(new File(
"/Users/TLQ/Desktop/a.xlsx"));
FileInputStream excellFile2 = new FileInputStream(new File(
"/Users/TLQ/Desktop/b.xlsx"));
// Create Workbook instance holding reference to .xlsx file
XSSFWorkbook workbook1 = new XSSFWorkbook(excellFile1);
XSSFWorkbook workbook2 = new XSSFWorkbook(excellFile2);
// Get first/desired sheet from the workbook
XSSFSheet sheet1 = workbook1.getSheetAt(0);
XSSFSheet sheet2 = workbook2.getSheetAt(0);
// add sheet2 to sheet1
addSheet(sheet1, sheet2);
excellFile1.close();
// save merged file
File mergedFile = new File(
"/Users/TLQ/Desktop/Albert.xlsx");
if (!mergedFile.exists()) {
mergedFile.createNewFile();
}
FileOutputStream out = new FileOutputStream(mergedFile);
workbook1.write(out);
out.close();
// mergeThemAll(mergedFile);
} catch (Exception e) {
e.printStackTrace();
}
}
public static void addSheet(XSSFSheet mergedSheet, XSSFSheet sheet) {
// map for cell styles
Map<Integer, XSSFCellStyle> styleMap = new HashMap<Integer, XSSFCellStyle>();
// This parameter is for appending sheet rows to mergedSheet in the end
int len = mergedSheet.getLastRowNum();
for (int j = sheet.getFirstRowNum(); j <= sheet.getLastRowNum(); j++) {
XSSFRow row = sheet.getRow(j);
XSSFRow mrow = mergedSheet.createRow(len + j + 1);
for (int k = row.getFirstCellNum(); k < row.getLastCellNum(); k++) {
XSSFCell cell = row.getCell(k);
XSSFCell mcell = mrow.createCell(k);
if (cell.getSheet().getWorkbook() == mcell.getSheet()
.getWorkbook()) {
mcell.setCellStyle(cell.getCellStyle());
} else {
int stHashCode = cell.getCellStyle().hashCode();
XSSFCellStyle newCellStyle = styleMap.get(stHashCode);
if (newCellStyle == null) {
newCellStyle = mcell.getSheet().getWorkbook()
.createCellStyle();
newCellStyle.cloneStyleFrom(cell.getCellStyle());
styleMap.put(stHashCode, newCellStyle);
}
mcell.setCellStyle(newCellStyle);
}
switch (cell.getCellType()) {
case HSSFCell.CELL_TYPE_FORMULA:
mcell.setCellFormula(cell.getCellFormula());
break;
case HSSFCell.CELL_TYPE_NUMERIC:
mcell.setCellValue(cell.getNumericCellValue());
break;
case HSSFCell.CELL_TYPE_STRING:
mcell.setCellValue(cell.getStringCellValue());
break;
case HSSFCell.CELL_TYPE_BLANK:
mcell.setCellType(HSSFCell.CELL_TYPE_BLANK);
break;
case HSSFCell.CELL_TYPE_BOOLEAN:
mcell.setCellValue(cell.getBooleanCellValue());
break;
case HSSFCell.CELL_TYPE_ERROR:
mcell.setCellErrorValue(cell.getErrorCellValue());
break;
default:
mcell.setCellValue(cell.getStringCellValue());
break;
}
}
}
}
答案 0 :(得分:2)
row.getCell(k)
, null
可以返回Cell
。有几种方法可以解决这个问题(例如,要求工作簿动态创建单元格),但对于这种情况,检查null Cell
是最容易且耗费资源最少的选项。