目前,我正在尝试使用python将多个Excel文件合并为一个。到目前为止,我的情况如下:
sharedDocs = "C:\\SPSharedDocuments\\*.xlsx"
invoices = "C:\\SPInvoices\\*.xlsx"
formsCerts = "C:\\SPForms&Certificates\\*.xlsx"
mgmt = "C:\\SPManagement\\*.xlsx"
files = [sharedDocs, invoices, formsCerts, mgmt]
for docs in files:
excel = []
for file in glob.glob(docs):
excel.append(file)
excels = [pd.ExcelFile(name) for name in excel]
frames = [x.parse(x.sheet_names[0], header=None, index_col=None) for x in excels]
frames_new = [df[1:] for df in frames[1:]]
combined = pd.concat(frames_new)
if sharedDocs == docs:
combined.to_excel("SharedDocsMerged.xlsx", header = False, index = False)
elif invoices == docs:
combined.to_excel("InvoicesMerged.xlsx", header = False, index = False)
elif formsCerts == docs:
combined.to_excel("FormsCertsMerged.xlsx", header = False, index = False)
else:
combined.to_excel("MGMTMerged.xlsx", header = False, index = False)
这有效,但是它不会复制第一个标题,因此我知道每列的名称是什么。在我将frames_new = [df[1:] for df in frames[1:]]
读为frames[1:] = [df[1:] for df in frames[1:]]
的行之前,但这导致同一文件的多个副本。
我所需要的就是复制一个标头,这样我就知道每一列的值。
非常感谢您的帮助。
更新:
我尝试使用下面的帖子暗示这是一个类似的问题,并且我编辑了代码,使其看起来像这样:
sharedDocs = "C:\\SPSharedDocuments\\*.xlsx"
invoices = "C:\\SPInvoices\\*.xlsx"
formsCerts = "C:\\SPForms&Certificates\\*.xlsx"
mgmt = "C:\\SPManagement\\*.xlsx"
files = [sharedDocs, invoices, formsCerts, mgmt]
for docs in files:
excel = []
for file in glob.glob(docs):
excel.append(pd.read_excel(file))
df = pd.concat(excel, ignore_index=True, sort = True)
if sharedDocs == docs:
df.to_excel("SharedDocsMerged.xlsx", header = False, index = False)
elif invoices == docs:
df.to_excel("InvoicesMerged.xlsx", header = False, index = False)
elif formsCerts == docs:
df.to_excel("FormsCertsMerged.xlsx", header = False, index = False)
else:
df.to_excel("MGMTMerged.xlsx", header = False, index = False)
我得到的结果是在左侧增加了2列,缺少了列,仍然没有标题。