我被要求为具有x，y和z坐标的数据集合编写BTS代码，其具有负数和正数，并且要求如下：
该程序能够根据数据集执行二叉树搜索。
请使用此电子邮件中提供的数据。它是X，Y和Z中坐标的集合
因此用户将输入X坐标，它将在输出中一起显示Y和Z，另一个是当用户想要搜索X的所有正/负时，它还将显示Y和Z X。 到目前为止我只知道二进制搜索只能对单个数字进行搜索，但不能对内部有3个数字的元素进行搜索。
这是X，Y和Z数据的少数集合，例如：
-0.090729 0.122568 0.030209 <--- one line of X Y Z coordinate
-0.179660 0.154953 0.033881
-0.335793 0.244996 0.269589
0.075957 0.149626 0.114472
我也将使用此代码作为基础
#include <cstdlib>
#include <iostream>
using namespace std;
int binary_search(int array[],int first,int last, int value);
int main() {
int list[10];
for (int k=0; k<11; k++)
list[k]=2*k+1;
cout<< "binary search results: "<< binary_search(list,1,21,11)<<endl;
return 0;
}//end of main
int binary_search(int array[],int first,int last, int search_key)
{
int index;
if (first > last)
index = -1;
else
{
int mid = (first + last)/2;
if (search_key == array[mid])
index = mid;
else
if (search_key < array[mid])
index = binary_search(array,first, mid-1, search_key);
else
index = binary_search(array, mid+1, last, search_key);
} // end if
return index;
}// end binarySearch
我还在考虑使用数组是不够的，我必须创建一个单独的文件，如数据库，用户可以使用一个输入搜索数据。 所以我有一个想法，我只为X坐标做二叉树，但是当用户输入X时，它会用数据集合中的X显示Y和Z，数据集合也很多，任何专家的将不胜感激:)仍然想知道二元搜索树是否能够做到这一点....
所以这是我需要使用的数据集合，有人可以告诉我如何制作能够从这个庞大的集合中调用数据的函数吗？
0.075957 0.149626 0.114472
0.000905 0.131220 0.031000
0.334059 -0.004790 0.207368
0.380561 -0.016845 0.110792
-0.083847 -0.009495 0.260374
0.316664 0.071467 0.120474
-0.307909 0.341245 -0.115581
0.411077 -0.098945 0.029724
-0.093728 0.413972 -0.045792
-0.445182 0.173948 0.306924
-0.339452 0.094466 0.338246
0.154974 0.153764 0.113986
0.383043 -0.017294 0.038540
0.371618 -0.036996 -0.034430
-0.488796 0.174331 0.109211
-0.425485 -0.003917 0.201166
-0.328634 0.319858 0.114390
-0.410262 0.298180 0.193996
0.155009 0.097454 0.225033
-0.225622 0.246139 0.118317
-0.399749 0.163849 0.335552
0.076578 0.133341 0.177679
-0.201047 0.142376 0.174390
-0.429153 -0.098775 -0.040573
0.230882 0.131755 0.118676
-0.483743 0.082920 0.040329
-0.078715 0.471042 -0.055900
-0.411718 0.237937 0.278383
-0.005249 0.003769 0.270521
-0.018101 0.489653 -0.124951
-0.133572 0.398057 -0.090000
0.154095 0.134174 0.180583
-0.172136 0.147088 0.112057
0.240332 0.079992 0.210373
-0.175250 0.391765 0.011504
-0.477955 0.162864 0.042821
-0.263429 0.246060 0.204495
0.408153 -0.094551 0.112774
0.388142 -0.103007 0.184936
-0.257106 0.309349 0.107726
-0.020619 0.343770 -0.051245
-0.366778 -0.278556 0.116261
-0.329815 0.313916 0.034602
-0.482418 0.071724 0.268572
0.296142 0.067455 0.185325
0.392588 -0.106540 -0.040632
-0.348415 0.380318 -0.132477
0.074743 0.098941 0.226089
0.313984 -0.095701 0.274736
-0.000127 0.359321 -0.099978
-0.389304 0.419894 -0.275472
-0.448952 -0.015681 0.018614
0.360441 0.017741 0.133138
0.072016 -0.429793 0.306404
0.157903 -0.423369 0.305657
-0.253995 0.329448 0.039563
-0.486770 0.073079 0.193422
-0.277697 0.136104 0.260296
-0.000924 0.131167 0.114723
-0.324768 0.304498 0.200203
-0.172816 0.407647 -0.040188
-0.262926 -0.426393 0.279458
-0.389169 0.326903 -0.115444
-0.171523 0.319164 0.036876
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0.021908 0.122344 0.172256
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-0.333589 0.232102 -0.053896
0.240226 -0.009687 0.271713
-0.125529 0.419457 -0.000220
-0.323461 0.062386 -0.069065
-0.335525 0.413992 -0.292639
-0.485317 0.253072 0.122003
0.160470 0.053417 0.252663
0.320594 -0.097082 -0.121452
0.153275 -0.012350 0.284012
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0.155106 0.152666 0.034476
0.237370 -0.432505 0.276914
0.213352 -0.110928 0.333017
0.076081 0.050562 0.261882
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-0.072565 -0.460061 0.025380
0.109360 -0.475999 0.064561
0.243323 -0.479673 0.126123
-0.110629 -0.489074 0.043599
0.151045 -0.483545 0.115056
0.113069 -0.479908 0.084853
0.336442 -0.463570 0.135023
0.076638 -0.459867 0.113200
-0.117317 -0.480495 0.113990
-0.002076 -0.459748 0.113895
-0.057473 -0.462636 0.113188
-0.256639 -0.489621 0.112012
0.123161 -0.463285 0.143835
0.181877 -0.477548 0.192178
0.151977 -0.457373 0.192210
0.076190 -0.455132 0.193957
-0.102975 -0.477424 0.189320
-0.067928 -0.459351 0.209563
-0.002745 -0.457144 0.191918
-0.161571 -0.485037 0.194232
0.216362 -0.476830 0.268931
-0.250727 -0.485793 0.193098
-0.320925 -0.308279 0.034877
0.072334 -0.480626 0.296205
-0.087828 -0.482461 0.282326
-0.003897 -0.482100 0.299386
如果我将所有数据放入data.txt文件并在main.cpp中读取它，这段代码是否可行？
int main ()
{
{
ifstream myReadFile;
myReadFile.open("Data.txt");
char output[100];
if (myReadFile.is_open())
{
while (!myReadFile.eof())
{
myReadFile >> output;
cout<<output;
}
}
myReadFile.close();
return 0;
}
这是顶点X的冒泡排序，我知道排序需要很长时间，但只要代码有效，时间就没关系了。
for (i=0; i<500-1; i++)
for (int j=i+1; j<500; j++)
if (X[i] > X[j])
{
int temp = X[i];
X[i] = X [j];
X[j] = temp;
temp = Y[i];
Y[i] = Y [j];
Y[j] = temp;
temp = Z[i];
Z[i] = Z [j];
Z[j] = temp;
}
答案 0 :(得分：1)
您谈论的是binary search trees，但您显示的代码在已排序的数组上执行了binary search。那不是一回事。
使用二进制搜索的一种方法是将X，Y和Z值放在一个数组或自定义结构中。类似的东西：
struct Vertex {
float X;
float Y;
float Z;
};
修改二进制搜索功能，使其获取这些结构的数组而不是整数数组。您必须使搜索键成为X浮点值：
int binary_search(Vertex array[],int first,int last, float x_value);
将X，Y，Z值加载到Vertex数组中，然后按X值排序：
bool vertexXComparator(const Vertex& lhs, const Vertex& rhs) {
return lhs.X < rhs.X;
}
std::sort(list, list+number_of_vertexes, vertexXComparator);
然后你应该能够在排序列表中使用二进制搜索（或std :: binary_search）。
我会谨慎使用float作为搜索键。 It is generally a bad idea测试浮点数是否相等。