Question

我有一个包含多个锻炼节点的图表。每个锻炼节点都与多种媒体，锻炼类型和身体焦点节点有关系。

以下各个查询均按预期工作并提供预期结果：

1）返回锻炼集和每个锻炼媒体：

MATCH (w:Workout)-[:hasMedia]->(m:Media) RETURN w.name as workout, collect(m.url) AS media

2）返回训练集和每种锻炼类型：

MATCH (w:Workout)-[:hasConcept]->(wt:Concept)-[:ofType]->(Category{name:"training"}) RETURN w.name AS workout, collect(wt.name) AS workoutType

3）返回一组训练，身体对每个训练集中：

MATCH (w:Workout)-[:hasConcept]->(bf:Concept)-[:ofType]->(Category{name:"bodyfocus"}) RETURN w.name AS workout, collect(bf.name) AS bodyFocus

此外，我有一组人员节点与锻炼有关系。

以下查询按预期工作并提供预期结果：

A）返回与特定人相关的训练集和原因（分数，证据）：

MATCH (Person{personId:"1028"})-[r:hasAffinity]->(c:Concept)<-[s]-(w:Workout) RETURN sum(toFloat(r.score)*toFloat(s.score))/count(c) AS score, w.name AS workout, collect({text:c.name, polarity:r.score, evidenceId:c.name}) AS evidence

我尝试做的事情（并且悲惨地失败）是针对单个复合查询得出的，它回答了以下问题：＆＃34;返回一组人的相关训练，包括得分，证据，媒体，锻炼类型，身体专注于每次锻炼＆＃34;。

似乎我想：匹配{A＆＃39; s path} with W MATCH w- {其余的1＆＃39; s}}，w- {其余的2＆＃39; s}}，w- {其余的3路径}返回{A＆＃39的东西}，{1＆＃39; s stuff}，{2＆＃39; s stuff}，{3＆＃39; s}}

...但我无法解决这个问题（因为新手可能对此方法有误）。帮助

Answer 1

我认为这是您在一个查询中组合所有内容所需要的：

// get the Workouts of a Person via the Concept
MATCH (p:Person {personId:"1028"})-[r:hasAffinity]->(c:Concept)<-[s]-(w:Workout)

// take the Person and Workout to the next step, calculate score and collect evidence
WITH DISTINCT p, w, sum(toFloat(r.score)*toFloat(s.score))/count(c) AS score, 
     collect({text:c.name, polarity:r.score, evidenceId:c.name}) AS evidence

// Match everything else for the workout
MATCH (w)-[:hasConcept]->(wt:Concept)-[:ofType]->(:Category {name:"training"})
MATCH (w)-[:hasConcept]->(bf:Concept)-[:ofType]->(:Category {name:"bodyfocus"})
MATCH (w)-[:hasMedia]->(m:Media)

// Return everything (score and evidence are available from the WITH statement)
RETURN p.personID, w.name AS workout, collect(wt.name) AS workoutType, 
    collect(bf.name) AS bodyFocus, collect(m.url) AS media, score, evidence

链接到多个并行子图匹配

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