一系列

Question

我尝试在python中创建一个程序，它基本上总结了一个小于0的项，如下所示： 1+((2X)/1!)+((3X^2)/2!)+((4X^3)/3!).... 我在系列中的每个术语设计了一个基本术语((A+1)((X)^A))/A!，其中A在循环中通过术语递增。下面的程序没有给出编译错误，但它没有显示结果。请帮忙。真的很感激。谢谢！

import decimal
def fact(n):
    if n == 0:
        return 1
    else:
        return n*(fact(n-1))
x = int(input("Enter the value of x"))
A=0
summation=0
sumt1=(A+1)
sumt2=(x**A)
sumt3=fact(x)
sumt4=sumt1*sumt2
sumt5=sumt4/sumt3

while (sumt5 > 0.00) :
    summation = summation+sumt5
    A+=1
finalsum=decimal.Decimal(1+summation)
print("The value is")
print(finalsum)

Answer 1

将sumt变量移动到while循环中，然后在sumt5 <= 0.00时突破循环：

import decimal

def fact(n):
    if n == 0:
        return 1
    else:
        return n*(fact(n-1))

x = 1  # Hardcoded for this example, instead of prompting.
A = 0
summation = 1.0

while True:
    sumt1 = A + 1
    sumt2 = x**A
    sumt3 = fact(A)  # Was `fact(x)` in original code, which didn't match your formula & prevented `sumt5 <= 0.00` from ever being true.
    sumt4 = sumt1 * sumt2
    sumt5 = sumt4/sumt3

    summation += sumt5
    A += 1

    if sumt5 <= 0.00:
        break


finalsum=decimal.Decimal(summation)
print("The value is {}.".format(finalsum))

更新答案

我想了解自己发生了什么变化，所以我将总结分解为一个单独的函数，而不是单独计算所有单独的术语，我将它们直接插入你在OP中给出的函数：{{ 1}}。这是我的代码：

((A+1)((X)^A))/A!

当我运行它时，我收到了以下输出：

import decimal

def factorial(n):
    if n == 0:
        return 1
    else:
        return n * factorial(n - 1)


def summation(num):
    A = 0
    result = 1.0

    while True:
        term = (A + 1) * num**A / factorial(A)
        result += term
        A += 1

        if term <= 0.0:  # Break out of the loop when the `term <= 0`.
            break

    return result


# Sample output.    
for i in range(1, 11):
    final = decimal.Decimal(summation(i))
    print('summation({}) == {}'.format(i, final))