我试图用Pyglet绘制一个圆圈但我失败了。但是,结果却是美丽而意想不到的。
我已经计算出数学:
我已经实施了这个方法:
""" Pyglet utilities. Designed to ease drawing of primitives with Pyglet. """
# Dependencies
import pyglet
from math import sin, cos
def circle(x, y, r, p, c, b): # p is number of points in circle EXCLUDING center
""" Adds a vertex list of circle polygon to batch and returns it. """
deg = 360 / p
P = x, y # P for POINTS
for i in range(p):
n = deg * i
P += int(r * cos(n)) + x, int(r * sin(n)) + y
return b.add(p+1, pyglet.gl.GL_TRIANGLE_FAN, None, ('v2i', P), ('c3B', (c)))
我写了一个测试:
""" This file tests the circle method of utilities module. """
# Dependencies
import pyglet
from utilities import circle
# Constants
WIN = 800, 800, 'TEST', False, 'tool' # x, y, caption, resizable, style
CENTER = WIN[0] // 2, WIN[1] // 2
RADIUS = 300
MAGENTA = (255, 0, 255)
WHITE = (255, 255, 255)
SPEED = 0.5 # in seconds
# Variables
win = pyglet.window.Window(*WIN)
batch = pyglet.graphics.Batch()
points = 1 # excluding center
def on_step(dt):
""" Logic performed every frame. """
global batch, points
batch = pyglet.graphics.Batch()
points += 1 # 2, 3, 4...
print (points + 1) # total number of points
circle(CENTER[0], CENTER[1], RADIUS, points, WHITE+MAGENTA*(points), batch)
@win.event
def on_draw():
""" Drawing perfomed every frame. """
win.clear()
batch.draw()
pyglet.clock.schedule_interval(on_step, SPEED)
pyglet.app.run()
这就是我所拥有的:
有人能指出我做错了吗?
答案 0 :(得分:1)
您需要将度数更改为弧度...(度/ 180)* pi是您需要的