这是我的阵列:
Array ( [HRI] => Array ( [0] => Array ( [0] => 14157.72 [1] => 10157.72 ) [1] => Array ( [0] => 39140.94 [1] => 39140.94 ) [2] => Array ( [0] => 36383.66 [1] => 36383.66 ) [3] => Array ( [0] => 38508.00 [1] => 38508.00 ) [4] => Array ( [0] => 8424.00 [1] => 8424.00 ) ) [MPU] => Array ( [0] => Array ( [0] => 432.00 [1] => 1200.00 ) ) [RHA] => Array ( [0] => Array ( [0] => 111562.50 [1] => 94237.50 ) [1] => Array ( [0] => 37880.00 [1] => 31400.00 ) [2] => Array ( [0] => 11364.00 [1] => 9420.00 ) [3] => Array ( [0] => 23719.50 [1] => 18832.50 ) [4] => Array ( [0] => 26705.00 [1] => 21800.00 ) [5] => Array ( [0] => 5190.00 [1] => 3816.00 ) [6] => Array ( [0] => 8707.50 [1] => 6966.00 ) [7] => Array ( [0] => 0.00 [1] => 0.00 ) [8] => Array ( [0] => 0.00 [1] => 0.00 ) [9] => Array ( [0] => 0.00 [1] => 0.00 ) [10] => Array ( [0] => 128952.00 [1] => 94500.00 ) [11] => Array ( [0] => 0.00 [1] => 0.00 ) ) [PBA] => Array ( [0] => Array ( [0] => 58816.26 [1] => 50784.36 ) ) )
我想浏览每个subArray并获取每列的总和。
E.g。
对于键为HRI
的子数组:
[HRI] =>
Array (
[0] => Array ( [0] => 14157.72 [1] => 10157.72 )
[1] => Array ( [0] => 39140.94 [1] => 39140.94 )
[2] => Array ( [0] => 36383.66 [1] => 36383.66 )
[3] => Array ( [0] => 38508.00 [1] => 38508.00 )
[4] => Array ( [0] => 8424.00 [1] => 8424.00 )
)
预期产出:
column 0: 14157.72 + 39140.94 + 36383.66 + 38508.00 + 8424.00 = ? column 1: 10157.72 + 39140.94 + 36383.66 + 38508.00 + 8424.00 = ?
我目前的代码:
$amount = [];
for($o=0;$o<count($totalamount);$o++){
print_r($totalamount[$o]['login']);
if($totalamount[$o]['login'] == $totalamount[$o]['login']){
//$amount[$totalamount[$o]['login']] += $totalamount[$o]['piamount'];
$piamount[$totalamount[$o]['login']][] = array_sum(array($totalamount[$o]['piamount'].','));
}
}
如何更改代码以获得预期结果?
答案 0 :(得分:1)
这应该适合你:
只需循环遍历数组,并使用array_sum()
foreach($arr as $k => $v)
echo $k . " = " . array_sum($v) . "<br>";
示例输入/输出:
$arr = [
[1,2,3],
[4,5,6],
[7,8,9],
];
输出:
0 = 6
1 = 15
2 = 24
修改强>
由于您更新了数组结构,只需使用:
foreach($arr as $k => $v)
echo $k . " = " . array_sum(array_map("array_sum", $v)) . "<br>";
编辑2:
如果你想要每个子数组数组的总和,你必须使用两个foreach循环,如下所示:
foreach($arr as $k1 => $innerArray) {
foreach($innerArray as $k2 => $v)
echo "$k1-$k2 = " . array_sum($v) . "<br>";
echo "<br><br>";
}
编辑3:
我想我终于看到了你想要的东西:你只想浏览每个子数组并得到子数组每列的总和:
foreach($arr as $k1 => $innerArray) {
foreach($innerArray[0] as $k2 => $v)
echo "$k1-$k2 = " . array_sum(array_column($innerArray, $k2)) . "<br>";
echo "<br><br>";
}
答案 1 :(得分:1)
$a=Array (
'HRI'=> Array (14157.72, 39140.94 , 36383.66,38508, 8424 ),
'RHA'=> Array (111562.5, 37880 , 11364 ,23719.5, 26705 ),
'PBA'=> Array (58816.26),
'MPU'=> Array (432 )
);
$sumHRI=0;
foreach ($a['HRI'] as $key=>$value) $sumHRI+=$value;
echo "HRI=$sumHRI";
更新问题:
$a=[
'HRI'=>[
[14157.72, 39140.94 , 36383.66,38508, 8424],
[14157.72, 39140.94 , 36383.66,38508, 8424],
[14157.72, 39140.94 , 36383.66,38508, 8424],
[14157.72, 39140.94 , 36383.66,38508, 8424],
],
'RHA'=>[111562.5, 37880 , 11364 ,23719.5, 26705 ],
'PBA'=> [58816.26],
'MPU'=> [432]
];
$sumArray=[];
foreach ($a as $k=>$bigArray){
$sumArray[$k]=0;
foreach($bigArray as $subArray) $sumArray[$k]+=array_sum($subArray);
echo "$k={$sumArray[$k]}";
}
如果我理解正确,你想要计算的总和。如果你想实际打印数字和符号+,必须在某处添加字符串连接。