Question

我一直在试图弄清楚如何正确执行此操作，并且我确定自己是一个白痴（这里是代码新手）。我有一个xml文件（如下所示），我正在解析并尝试根据节点＆＃34; testset＆＃34;为每个数据集构建多个表。 xml文件不会改变它的设计方式，但会增加多少＆＃34; testsets＆＃34;有。我有下面的代码。

我目前有testspassed和testpasssed显示我需要的2个数组，但我无法弄清楚如何将每个数组的总和分开（并期望在更远的地方将有未知数量的数组）然后我必须把它写到桌子上。下面的代码目前在传递的测试中将数组的两个部分加在一起，我需要将它们分开。所以我希望数组设置为137,70。我很感谢任何帮助或建议。

XML

<?xml version="1.0" encoding="utf-8"?>
<TestSets>
  <TestSet>
    <TestSetID>TestSet_iOS1</TestSetID>
    <Hardware>iPad Air 2</Hardware>
    <Version>iOS 8.3</Version>
    <Build>Pro 2.7.0.13 </Build>
    <Orientation>PORTRAIT</Orientation>
    <NumTestCases>46</NumTestCases>
    <NumTestScripts>17</NumTestScripts>
    <TotalTime>230891.363</TotalTime>
    <TestResults>
      <TestRun>
        <Date>24 Mar 2015 09:12:00</Date>
        <Hardware>iPad Air 2</Hardware>
        <Version>iOS 8.1.3</Version>
        <Build>2.7.0.607</Build>
        <Orientation>PORTRAIT</Orientation>
        <NumPassed>37</NumPassed>
        <NumFailed>31</NumFailed>
      </TestRun>
      <TestRun>
        <Date>27 Mar 2015 11:43:18</Date>
        <Hardware>iPad Air 2</Hardware>
        <Version>iOS 8.1.3</Version>
        <Build>Pro 2.7.0.615</Build>
        <Orientation>PORTRAIT</Orientation>
        <NumPassed>100</NumPassed>
        <NumFailed>25</NumFailed>
      </TestRun>
     </TestResults>
  </TestSet>
  <TestSet>
    <TestSetID>TestSet_iOS2</TestSetID>
    <Hardware>iPad Air 2</Hardware>
    <Version>iOS 8.1.3</Version>
    <Build>Pro 2.7.0.623</Build>
    <Orientation>LANDSCAPE</Orientation>
    <NumTestCases>38</NumTestCases>
    <NumTestScripts>9</NumTestScripts>
    <TotalTime>20800.255</TotalTime>
    <TestResults>
      <TestRun>
        <Date>30 Mar 2015 10:29:00</Date>
        <Hardware>iPad Air 2</Hardware>
        <Version>iOS 8.1.3</Version>
        <Build>2.7.0.615</Build>
        <Orientation>LANDSCAPE</Orientation>
        <NumPassed>34</NumPassed>
        <NumFailed>15</NumFailed>
      </TestRun>
      <TestRun>
        <Date>31 Mar 2015 20:00:02</Date>
        <Hardware>iPad Air 2</Hardware>
        <Version>iOS 8.1.3</Version>
        <Build>Pro 2.7.0.620</Build>
        <Orientation>LANDSCAPE</Orientation>
        <NumPassed>10</NumPassed>
        <NumFailed>19</NumFailed>
      </TestRun>
      <TestRun>
        <Date>02 Apr 2015 10:15:25</Date>
        <Hardware>iPad Air 2</Hardware>
        <Version>iOS 8.1.3</Version>
        <Build>Pro 2.7.0.623</Build>
        <Orientation>LANDSCAPE</Orientation>
        <NumPassed>26</NumPassed>
        <NumFailed>12</NumFailed>
      </TestRun>
    </TestResults>
  </TestSet>
</TestSets>

当前代码

 document.write("<table><tr><th><st>Test Set ID</st></th><th>Hardware</th><th>Op Sys Version</th><th>App Build</th><th>Orientation</th><th>Number of Test Passed</th><th>Number of Test Failed</th></tr>");
var x = xml.getElementsByTagName("TestSet");
var sum = 0;
for (i = 0; i < x.length; i++) {
    document.write("<tr class='dynamictable'><td>");
    document.write(x[i].getElementsByTagName("TestSetID")[0].childNodes[0].nodeValue);
    document.write("</td><td>");
    document.write(x[i].getElementsByTagName("Hardware")[0].childNodes[0].nodeValue);
    document.write("</td><td>");
    document.write(x[i].getElementsByTagName("Version")[0].childNodes[0].nodeValue);
    document.write("</td><td>");
    document.write(x[i].getElementsByTagName("Build")[0].childNodes[0].nodeValue);
    document.write("</td><td>");
    document.write(x[i].getElementsByTagName("Orientation")[0].childNodes[0].nodeValue);
    var y = x[i].getElementsByTagName("TestRun");
    var testspassed = [];
    var testsfailed = [];
    for (j = 0; j < y.length; j++) {
        testspassed.push(y[j].getElementsByTagName("NumPassed")[0].childNodes[0].nodeValue);
        testsfailed.push(y[j].getElementsByTagName("NumFailed")[0].childNodes[0].nodeValue);
    }

    for (var k=0; k<testspassed.length; k++){
    sum+=testspassed[k]<<0;   
}
console.log(sum);

}

Javascript得到每个数组的总和

0 个答案: