Java enum getter

Question

我很感激这里的任何帮助。

执行以下代码，Buyer2 ID始终覆盖buyer1 ID。意味着我总是得到ID = 2。我不确定以下代码有什么问题。我认为这是我的枚举和get方法始终保留最后一个值。

Buyer bOne = new Buyer("buyer1", 1); 
Buyer bTwo = new Buyer("buyer2", 2);

其余代码：

public enum Fruits {
    Banana("banana", "B"),
    Apple("apple","A"),
    Orange("orange","O");

    private String type, ID;

    private Fruits(String type, String ID){
        this.type = type;
        this.ID = ID;
    }

    public String getType() {
        return type;
    }

    public String getID() {
        return ID;
    }

    public void setID(String ID){
        this.ID = ID;
    }
}

public class Player {
    private String name;
    private Fruits banana, apple, orange;

    private int ID;

    public buyer(String name, int ID) {
        this.name = name;
        this.ID = ID;
        banana = Fruits.Orange;
        apple = Fruits.Apple;
        orange = Fruits.Orange;

        banana.setID("B"+ID);
        apple.setID("A"+ID);
        Orange.setID="O"+ID;
    }
}

感谢

Answer 1

你的Fruits枚举是可变的，这可能不是你想要的。 setID()上的Fruits方法可能是设计错误。由于不同的水果（Banana，Apple，...）是一个单一的实例，通过你的所有程序共享，他们需要反映一些globabl状态，而不是某些特定于买家的状态。

尝试删除此setter，看看是否可以重构代码......

Answer 2

Fruits.java

   package test;
    public class Buyer {
    private String name;
    private Fruits banana, apple, orange;

    private int ID;


    public Buyer(String name, int ID) {
        this.name = name;
        this.ID = ID;
        banana = Fruits.Orange;
        apple = Fruits.Apple;
        orange = Fruits.Orange;

        banana.setID("B"+ID);
        apple.setID("A"+ID);
        orange.setID("O"+ID);

    }
    public static void main (String  []args){

            Buyer bOne = new Buyer("buyer1", 1); 
    System.out.println("id = " + bOne.ID + " name =" + bOne.name);
    Buyer bTwo = new Buyer("buyer2", 2);
    System.out.println("id = " + bTwo.ID  + " name =" + bTwo.name);
    }
    }

Buyer.java

function loadSave(){
    var saveData = $("#saveText").text();
    var pieceData = saveData.split("|");
    var posData = [];

    var puzzleInfo = pieceData[0].split(",");
    createGrid(parseInt(puzzleInfo[1]));
    createPieces(parseInt(puzzleInfo[1]), puzzleInfo[0]);

    oldSource = imgSource;
    imgSource = puzzleInfo[0];
    console.log(saveData);
    $("#puzzleContainer img").attr("src", imgSource);

    for(i=1; i < pieceAmount+1; i++){
        posData = pieceData[i].split(";");
        $(".piece:nth-child("+i+")").css({
            top: posData[0],
            left: posData[1],
        });
    }

    $( "#pieceAmount" ).slider({
        value: puzzleInfo[1],
    });
    $("#pieceAmountValue").html(puzzleInfo[1]*puzzleInfo[1]);
}

对consol的结果：

id = 1 name = buyer1

id = 2 name = buyer2

Answer 3

也许检查你的最后一行：）

$re = '(?s)^<{LANGB}^>(.*)^^.*^<{/LANGB}^>';^

Answer 4

枚举的每个实例都保证只构造一次，因此最后一个值保留。