Question

我有这个功能

def getInput(rows, cols, myList):
    myList = [[0]*(cols-2) for i in range(rows-2)] #creates the board
    for i in myList: # adds -1 to beginning and end of each list to make border
        i.append(-1)
        i.insert(0,-1)
    myList.insert(0,[-1]*(cols)) #adds top border
    myList.append([-1]*(cols)) #adds bottom border

    while True:
        rows = input("Please enter the row of a cell to turn on or 'q' to exit: ")
        if rows == 'q': # if q then end while loop
            break
        cols = input("Please enter the column of a cell to turn on: ")
        print()
        myList[int(rows)][int(cols)] = 1 # changes chosen cells from 0(dead) to 1(alive)
    return myList

我需要知道一种方法来使这个功能不间断或继续使用。

Answer 1

我认为应该这样做：

...
rows = ""
while rows != 'q':
    rows = input("Please enter the row of a cell to turn on or 'q' to exit: ")
    if rows != 'q': # if q then end while loop
        cols = input("Please enter the column of a cell to turn on: ")
        print()
        myList[int(rows)][int(cols)] = 1 # changes chosen cells from 0(dead) to 1(alive)
return myList

只有当行不为True时才进入if块，如果在任何运行中，行被初始化为"q"，则while循环将在下一次运行时自动终止。

Answer 2

您可以拥有一个包含布尔True值的变量，并且可以在False所需的基本条件下转为if rows == 'q':。

status = True
while status:
    rows = input("Please enter the row of a cell to turn on or 'q' to exit: ")
    if rows == 'q':
        status = False
        continue
    cols = input("Please enter the column of a cell to turn on: ")
    print()
    myList[int(rows)][int(cols)] = 1
return myList

如果您不想同时使用break和continue声明。比你应该返回myList，因为它将从你的函数中退出，终止while循环。

if rows == 'q':
    return myList

Answer 3

如何使用else以避免需要继续。

def getInput(rows, cols, myList):
    myList = [[0]*(cols-2) for i in range(rows-2)] #creates the board
    for i in myList: # adds -1 to beginning and end of each list to make border
        i.append(-1)
        i.insert(0,-1)
    myList.insert(0,[-1]*(cols)) #adds top border
    myList.append([-1]*(cols)) #adds bottom border
    run = True

    while run:
        rows = input("Please enter the row of a cell to turn on or 'q' to exit: ")
        if rows == 'q': # if q then end while loop
            run = False
        else:
            cols = input("Please enter the column of a cell to turn on: ")
            print()
            myList[int(rows)][int(cols)] = 1 # changes chosen cells from 0(dead) to 1(alive)
    return myList

Python Make函数不间断或继续

3 个答案: