Python中二进制搜索树的深度

时间:2015-03-31 21:50:44

标签: python binary-search-tree depth

在我的二分查找树中,我正在创建一个深度函数,它将告诉用户他们插入的树的深度是多少。此功能对于我的唯一删除功能至关重要,该功能可从最大深度侧节点删除节点。我想我知道问题究竟在哪里,但我不确定。

这是我一直接受的错误。

C:\Python33\python.exe "C:/Users/koopt_000/Desktop/College/Sophomore Semester 2/Computer Science 231/Chapter7/Test.py"
Traceback (most recent call last):
PRE-ORDER TRANSVERSE:
  File "C:/Users/koopt_000/Desktop/College/Sophomore Semester 2/Computer Science 231/Chapter7/Test.py", line 19, in <module>
4
    print("The max depth of the tree is,", a.height(tree),"nodes deep.")
2
  File "C:\Users\koopt_000\Desktop\College\Sophomore Semester 2\Computer Science 231\Chapter7\BinarySearchTree.py", line 245, in height
1
3
7 
6 
5
10
None
IN-ORDER TRANSVERSE:
1
2
3
4
5
6
7
10
None
POST-ORDER TRANSVERSE:
1
    return max(BST.height(root.left), BST.height(root.right)) + 1
3
TypeError: height() missing 1 required positional argument: 'root'
2
5
6
10
7
4
None

Process finished with exit code 1

现在我认为我的问题出现在这部分代码中:

return max(BST.height(root.left), BST.height(root.right)) + 1

我相信这个陈述是导致它的原因,因为它让我调用了BST功能,高度功能已经用于其工作&#39;。我只是尝试了#34; height。(root.left)&#34;,它没有用,因为它说没有全局变量高度。这不是我不相信的情况。

这是我的函数代码的完整列表,从我的树节点开始,然后是我的BST文件(main),然后是我的测试代码。

class TreeNode(object):

    def __init__(self, data = None, left=None, right=None):
        self.item = data
        self.left = left
        self.right = right

    def __str__(self):
        return str(self.item)

from TreeNode import TreeNode


class BST(object):

    #------------------------------------------------------------

    def __init__(self):

        """create empty binary search tree
        post: empty tree created"""

        self.root = None
        self.size = 0

    def delete(self, item):

        """remove item from binary search tree
        post: item is removed from the tree"""

        self.root = self._subtreeDelete(self.root, item)

    #------------------------------------------------------------

    def _subtreeDelete(self, root, item):

        if root is None:   # Empty tree, nothing to do
            return None
        if item < root.item:                             # modify left
            root.left = self._subtreeDelete(root.left, item)
        elif item > root.item:                           # modify right
            root.right = self._subtreeDelete(root.right, item)
        else:                                            # delete root
            if root.left is None:                        # promote right subtree
                root =  root.right
            elif root.right is None:                     # promote left subtree
                root = root.left
            else:
                # root node can't be deleted, overwrite it with max of 
                #    left subtree and delete max node from the subtree
                root.item, root.left = self._subtreeDelMax(root.left)
        return root

 def _subtreeDelMax(self, root):

        if root.right is None:           # root is the max 
            return root.item, root.left  # return max and promote left subtree
        else:
            # max is in right subtree, recursively find and delete it
            maxVal, root.right = self._subtreeDelMax(root.right)
            return maxVal, root  

   def height(self, root):
        if root is None:
            return 0
        else:
            return max(BST.height(root.left), BST.height(root.right)) + 1

from BinarySearchTree import BST
from TreeNode import TreeNode

tree = TreeNode(4, TreeNode(2, TreeNode(1), TreeNode(3)), TreeNode (7, TreeNode(6),TreeNode(9)))


a = BST()
a._subtreeInsert(tree, 10)
a._subtreeInsert(tree, 5)
a._subtreeDelete(tree, 9)

print("PRE-ORDER TRANSVERSE:")
print(a.preOrder(tree))
print("IN-ORDER TRANSVERSE:")
print(a.inOrder(tree))
print("POST-ORDER TRANSVERSE:")
print(a.postOrder(tree))

print("The max depth of the tree is,", a.height(tree),"nodes deep.")
print("There are,", a.treeSize(tree),"nodes in this tree.")

有没有人看到我的身高功能不能正常工作的原因?谢谢!

1 个答案:

答案 0 :(得分:2)

您的函数height是类BST的实例方法,您需要通过self而不是类BST来调用它。 所以在你的特殊情况下,这是:

def height(self, root):
    if root is None:
        return 0
    else:
        return max(self.height(root.left), self.height(root.right)) + 1

但是,您的函数height实际上并不依赖于与搜索树直接关联的任何数据。仅需要self来继续递归。因此,您还可以通过staticmethod decorator将其转换为静态方法:

@staticmethod
def height(root):
    if root is None:
        return 0
    else:
        return max(BST.height(root.left), BST.height(root.right)) + 1

或者,您也可以将该功能完全移出BST课程,然后摆脱BST.height,然后通过height进行调用。

从您发布的代码中,这基本上适用于BST类的所有功能。我真的不需要它。您只能在python模块中使用TreeNode和一些顶级函数(没有BST类)来修改树并与之交互。