Question

我有一个迭代记录类型列表的函数：

let resAddr (ranges: IpRanges list) =
    ranges
    |> List.iter (fun e ->
                 {
                    let {ipStart=ipStart;ipEnd=ipEnd;subnet=subnet;gateway=gateway} = e
                    printfn "%O" ipStart
                 })

编译器抱怨错误

Invalid record, sequence or computation expression. Sequence expressions should be of the form 'seq { ... }'

我做错了什么？

Answer 1

不要将函数体放在括号中，F＃不使用大括号，它使用空格。因此，请确保正确识别您的功能。

let resAddr (ranges: IpRanges list) =
    ranges
    |> List.iter (fun e ->
                      let { ipStart=ipStart; ipEnd=ipEnd; subnet=subnet; gateway=gateway } = e
                      printfn "%O" ipStart
                 )

另外，我发现当我的函数变成多行时，我通常更喜欢单独声明它们以帮助提高可读性

let resAddr (ranges: IpRanges list) =
    let internalHandleRange range =
        let { ipStart=ipStart; ipEnd=ipEnd; subnet=subnet; gateway=gateway } = range
        printfn "%O" ipStart
    ranges
    |> List.iter internalHandleRange

无效的记录，序列或计算表达式

1 个答案: