飞机正常最靠近原点的平面点 - matlab

Question

我试图在最接近原点的飞机上找到一个点。当我绘制法线时，不知何故它不垂直于飞机！此外，距离原点最近的平面上的点在图中看起来不正确。我无法弄清楚出了什么问题。有任何想法吗？

c = 2;
x1 = [1, 0, 0] * c;
x2 = [0, 1, 0] * c;
x3 = [0, 0, 1] * c;

x = [x1(1), x2(1), x3(1)];
y = [x1(2), x2(2), x3(2)];
z = [x1(3), x2(3), x3(3)];
figure(1); plot3(x,y,z,'*r'); hold on; grid on;

normal = cross(x1-x2, x1-x3);
% Find all coefficients of plane equation
D = -dot(normal, x1);
range = [-10 10]; [X, Z] = meshgrid(range, range);
Y = (-normal(1) * X - normal(3) * Z - D)/ normal(2);
order = [1 2  4 3]; patch(X(order),Y(order),Z(order),'b');
alpha(0.3); 

plot3([x(1), x(3)], [y(1), y(3)], [z(1), z(3)]);
plot3([x(1), x(2)], [y(1), y(2)], [z(1), z(2)]);
x1=x1-x3;
plot3([normal(1), x1(1)], [normal(2), x1(2)], [normal(3), x1(3)], 'k');

%% Get the point on the plane closest point to (0,0,0)
p = normal * (-D / sum(normal.^2,2));
plot3(p(1), p(2), p(3), '*g');

感谢您的帮助。

Answer 1

规范你的正常：

normal = normal /norm(normal);

正确绘制法线：

plot3([x1(1)+normal(1), x1(1)], [x1(2)+normal(2), x1(2)], [x1(3)+normal(3), x1(3)], 'k');

并且为了进行适当的可视化，轴应具有相同的比例：

axis equal

看起来不错，是吗？