我有结构内部结构,结构看起来像
struct tDeviceProperty {
DWORD Tag;
DWORD Size;
union _DP value;
};
typedef union _DP
{
short int i;
LONG l;
ULONG ul;
float flt;
double dbl;
BOOL b;
double at;
FILETIME ft;
LPSTR lpszA;
LPWSTR lpszW;
LARGE_INTEGER li;
struct tBinary bin;
BYTE reserved[40];
} __UDP;
struct tBinary {
ULONG size;
BYTE * bin;
};
来自tBinary结构bin的必须转换为tImage(结构如下)
struct tImage {
DWORD x;
DWORD y;
DWORD z;
DWORD Resolution;
DWORD type;
DWORD ID;
diccid_t SourceID;
const void *buffer;
const char *Info;
const char *UserImageID;
};
在c#中使用相同的东西我已经完成了编组,但在将指针转换为结构时没有给出正确的值。 C#代码如下,
tBinary tBin = new tBinary();
IntPtr tBinbuffer = Marshal.AllocCoTaskMem(Marshal.SizeOf(tBin));
Marshal.StructureToPtr(tBin.bin, tBinbuffer, false);
tDeviceProperty tDevice = new tDeviceProperty();
tDevice.bin = tBinbuffer;
IntPtr tDevicebuffer = Marshal.AllocCoTaskMem(Marshal.SizeOf(tDevice));
Marshal.StructureToPtr(tDevice.bin, tDevicebuffer, false);
Battary tbatt = new Battary();
tbatt.value = tDevicebuffer;
IntPtr tbattbuffer = Marshal.AllocCoTaskMem(Marshal.SizeOf(tbatt));
Marshal.StructureToPtr(tbatt.value, tbattbuffer, false);
result = GetDeviceProperty(ref tbattbuffer);
Battary v = (Battary)Marshal.PtrToStructure(tbattbuffer, typeof(Battary));
tDeviceProperty v2 = (tDeviceProperty)Marshal.PtrToStructure(tDevicebuffer, typeof(tDeviceProperty));
tBinary v3 = (tBinary)Marshal.PtrToStructure(tBinbuffer, typeof(tBinary));
[StructLayout(LayoutKind.Explicit)]
public struct tDeviceProperty
{
[FieldOffset(0)]
[MarshalAs(UnmanagedType.U2)]
public ushort i;
[FieldOffset(2)]
[MarshalAs(UnmanagedType.I4)]
public int l;
[FieldOffset(6)]
[MarshalAs(UnmanagedType.U4)]
public uint ul;
[FieldOffset(10)]
[MarshalAs(UnmanagedType.R4)]
public float flt;
[FieldOffset(14)]
[MarshalAs(UnmanagedType.R8)]
public double dbl;
[FieldOffset(22)]
[MarshalAs(UnmanagedType.I4)]
public int b;
[FieldOffset(26)]
[MarshalAs(UnmanagedType.R8)]
public double at;
[FieldOffset(34)]
//[MarshalAs(UnmanagedType.Struct)]
public IntPtr ft;
[FieldOffset(42)]
//[MarshalAs(UnmanagedType.Struct)]
public IntPtr lpszA;
[FieldOffset(43)]
//[MarshalAs(UnmanagedType.Struct)]
public IntPtr lpszW;
[FieldOffset(45)]
[MarshalAs(UnmanagedType.U8)]
public ulong li;
[FieldOffset(53)]
[MarshalAs(UnmanagedType.Struct)]
public IntPtr bin;
[FieldOffset(61)]
//[MarshalAs(UnmanagedType.Struct)]
public IntPtr reserved;
}
[StructLayout(LayoutKind.Sequential)]
public struct tBinary
{
public int size;
public IntPtr bin;
}
[StructLayout(LayoutKind.Sequential)]
public struct Battary
{
public uint Tag;
public uint Size;
public IntPtr value;
}
[StructLayout(LayoutKind.Sequential)]
public struct tDiccBatteryStatus
{
public uint RefreshWear;
public uint TotalWear;
public ushort Voltage;
public ushort Battery;
public int BatteryOK;
public int NeedRefresh;
public int NeedChange;
public ushort Temperature;
public int Charge;
public byte State;
public byte ExternalPowered;
public int CapacityLeft;
}
答案 0 :(得分:0)
我认为失败的原因是tDeviceProperty
声明。事实上,它的成员value
是一个联合,但是在tDeviceProperty中你应用constatly增加偏移量,而它们应该具有相同的值。
这是因为联盟成员从相同的偏移开始,共享其他成员的相同空间。 union的大小由union中声明的字段的最大大小决定。
确实,使用您的代码:
[StructLayout(LayoutKind.Explicit, Size = )]
public struct tDeviceProperty
{
[FieldOffset(0)]
[MarshalAs(UnmanagedType.U2)]
public ushort i;
[FieldOffset(2)]
[MarshalAs(UnmanagedType.I4)]
public int l;
[FieldOffset(6)]
[MarshalAs(UnmanagedType.U4)]
public uint ul;
[FieldOffset(6)]
[MarshalAs(UnmanagedType.R4)]
public float flt;
[FieldOffset(6)]
[MarshalAs(UnmanagedType.R8)]
public double dbl;
[FieldOffset(6)]
[MarshalAs(UnmanagedType.I4)]
public int b;
[FieldOffset(6)]
[MarshalAs(UnmanagedType.R8)]
public double at;
[FieldOffset(6)]
//[MarshalAs(UnmanagedType.Struct)]
public IntPtr ft;
[FieldOffset(6)]
//[MarshalAs(UnmanagedType.Struct)]
public IntPtr lpszA;
[FieldOffset(6)]
//[MarshalAs(UnmanagedType.Struct)]
public IntPtr lpszW;
[FieldOffset(6)]
[MarshalAs(UnmanagedType.U8)]
public ulong li;
[FieldOffset(6)]
[MarshalAs(UnmanagedType.Struct)]
public IntPtr bin;
[FieldOffset(6)]
//[MarshalAs(UnmanagedType.Struct)]
public IntPtr reserved;
}
另请查看我最近的question/answer。