Question

我想要一些算法来构建一个PHP升级系统我已经建立了一个系统来升级人们，但是如果人们获得了大量的exp，那么他们需要多次升级我的代码示例：

if(isset($_POST['id']) && isset($_POST['amount'])) { $amount = $_POST['amount']; $user = $_POST['id']; $exp;$etnl;$newExp;$level;

    `//select exp and etnl from DB 
    $result = DB::getInstance() ->query("SELECT exp,etnl,level FROM exp WHERE id = $user");
    $result->setFetchMode(PDO::FETCH_ASSOC);
    $row = $result->fetch();
    $exp = $row['exp'];
    $etnl = $row['etnl'];
    $level =  $row['level']
    //c where to level up user or to add exp to his ep bar
    if($amount + $exp > $etnl) {
        $etnl = $etnl * 2;
        $leftOvers = ($amount + $exp) - $etnl;
        $newExp = $leftOvers;
        $level = $level + 1;`


    $result = DB::getInstance()->prepare("UPDATE exp SET exp=?,level=?,etnl=? WHERE id=?");
    $result->execute(array($amount,$level,$etnl,$user));
    } else {
        $result = DB::getInstance()->prepare("UPDATE exp SET exp=? WHERE id=?");
        $result->execute(array($amount,$user));

    }
}`

` 但是如果exp可以将任何帮助或任何新代码提升2倍，那么这个系统会失败吗？ BTW etnl代表exp到下一级谢谢

Answer 1

你必须得到一个水平表，基本上是[exp，level]对的列表。例如，

$level_list = [
    ['exp' => 0, 'level' => 1],
    ['exp' => 100, 'level' => 2],
    ['exp' => 1000, 'level' => 3],
    // etc.
];

然后，从结尾开始迭代表：

$i = count($level_list);

while($i > 0) {
    $i--;
    if ($user_exp >= $level_list[i]['exp']) {
        // this is the level we need
        break;
    }
}

$target_level = $level_list[$i]['level'];
$target_exp = $level_list[$i]['exp'];

Answer 2

如果您不想像其他答案一样手动输入关卡表，您也可以尝试使用递归函数进行处理：

$current_exp = 0;
$current_level = 1;
$to_next_level = 1000;

function did_level( $amount = 0 ) {
    global $current_exp;
    global $curent_level;
    global $to_next_level;

    $tmp_amount = $amount + $current_exp;
    $tmp_amount_remainder = $tmp_amount - $to_next_level;

    if ($tmp_amount >= $to_next_level) {

        $current_level++;
        $to_next_level *= 2;
        $current_exp = $tmp_amount;

        if ($tmp_amount_remainder > 0) {
            // Level us up again.
            did_level( $tmp_amount_remainder );
        } else {
            // Store the new level, to next level, and current exp
        }

    } else {
        // Store the new exp amount
    }

}

升级PHP算法

2 个答案: