Question

正如标题所说，我试图在第一季度以及第二季度2.0-2.9之间显示0.1-1.9之间的数字，这就是我到目前为止所尝试的数据

 $sql="SELECT Patch_No, Created FROM info ORDER BY Patch_NO DESC";

        $result = $conn->query($sql);
        while($data = $result->fetch_assoc()){
            if(!isset($seasons[ceil($data['Patch_No'])])||is_int($data['Patch_No'])&&ceil($data['Patch_No'])==$data['Patch_No']+1){

                $seasons[ceil($data['Patch_No'])]=ceil($data['Patch_No']);
                echo '<hr><i>SEASON '.ceil($data['Patch_No']).'<br></i><hr>';

            }

            echo '<a href="delete_patch.php?Patch_No='.$data['Patch_No'].'" alt="'.$data['Created'].'" title="'.$data['Created'].'">
            '.$data['Patch_No'].'</a><br>';

        }
        echo '<hr><hr><a href="index.php">CMS</a>';

结果如下：http://i.imgur.com/VeN8pD8.png非常接近

Answer 1

您可以在SQL中轻松推导出季节。例如，在MySQL中，您可以使用substring_index()：

SELECT Patch_No, Created, SUBSTRING_INDEX(Patch_No, '.', 1) as Season
FROM info
ORDER BY Patch_NO DESC;

其他数据库具有可用于此目的的类似功能。

请注意，这只是从Patch_No中提取第一个数字，这似乎是您的意图。

这实际上将0.1-0.9与1.0分开，这对我来说很有意义。如果您想将这些作为一个季节，您可以使用case声明。

SELECT Patch_No, Created,
       (CASE WHEN Patch_No like '%0' THEN '1'
             ELSE SUBSTRING_INDEX(Patch_No, '.', 1)
        END) as Season
FROM info
ORDER BY Patch_NO DESC;

显示0.1-1.9,2.0-2.9等之间的数字，

1 个答案: