Question

我知道可以使用

生成整数随机数

(rand() % (difference_between_upper_and_lower_limit)) + lower_limit

我想知道是否有一种方法可以生成介于0.1和0.01之间的数字。我试过了 double speed = (rand() % 10)/100; 但这总是给我0.0000000；预先谢谢！！

Answer 1

我认为，您错过了类型转换部分==> （（double）（rand（）％10））/ 100;

尝试此代码。

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main(void) {
  // If you don't set the seed-value, you'll always get the same random numbers returned in every execution of the code
  srand(time(0));

  double speed = ((double)(rand() % 10))/100;
  printf("%f\n", speed );

  speed = ((double)(rand() % 10))/100;
  printf("%f\n", speed );

  speed = ((double)(rand() % 10))/100;
  printf("%f\n", speed );

  speed = ((double)(rand() % 10))/100;
  printf("%f\n", speed );

  return 0;
}

Answer 2

您可以使用以下任意间隔创建均匀分布

((double)rand()/RAND_MAX)*(i_end-i_start)+i_start

其中i_start和i_end表示间隔的开始和结束。

在您的情况下，请尝试

((double)rand()/RAND_MAX)*0.09+0.01

Answer 3

double upper_limit = .1;
double lower_limit = .01;
double value = ((upper_limit-lower_limit)*rand())/RAND_MAX + lower_limit;

如何生成0.1到0.01之间的随机数

3 个答案: