Question

我正在尝试检测我的精灵节点是否被触摸过，我不知道从哪里开始。

let Pineapple = SKSpriteNode(imageNamed: "Pineappleimg")
Pineapple.userInteractionEnabled = true
Pineapple.position = CGPoint(x: CGRectGetMidX(self.frame) - 200, y: CGRectGetMidY(self.frame));
self.addChild(Pineapple)

Answer 1

首先将name的{{1}}属性设置为字符串。

SKSpriteNode

然后在pineapple.name = "pineapple" pineapple.userInteractionEnabled = false

中的touchesBegan函数中

Scene

这是一种方法。
您也可以继承override func touchesBegan(touches: NSSet, withEvent event: UIEvent) { let touch:UITouch = touches.anyObject()! as UITouch let positionInScene = touch.locationInNode(self) let touchedNode = self.nodeAtPoint(positionInScene) if let name = touchedNode.name { if name == "pineapple" { print("Touched") } } }并覆盖其中的SKSpriteNode。

touchesBegan

然后做

class TouchableSpriteNode : SKSpriteNode
{
    override func touchesBegan(touches: NSSet, withEvent event: UIEvent) {
        print("touched")
    }
}

Answer 2

如果您只查找可以触摸的几个节点（例如，游戏UI中的“继续”或“退出”标签），这可能是一种替代但非常简单的解决方案：

override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) {
    let touch = touches.first!
    if myNode.containsPoint(touch.locationInNode(self)) {
        print("touched")
    }
}

Answer 3

更新Swift Swift版本 3.0.2 （swiftlang-800.0.63 clang-800.0.42.1）和XCode版本 8.2.1 （8C1002）：

“Set”类型的值没有成员“ anyObject ”

' locationInNode '已重命名为'location（in：）'

' nodeAtPoint '已重命名为'atPoint（_：）'

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
    for touch in touches {
        let location = touch.location(in: self)
        let node : SKNode = self.atPoint(location)
        if node.name == "myNodeName" {
            print("Hello")
        }
    }
}

Answer 4

这将检测 Xcode 9.2 Swift 4.0

中的触摸

{{1}}

Answer 5

Swift 3 在SKSpriteNode的子类中嵌入触控功能的答案：

class SpriteSub: SKSpriteNode {

    init() {
        super.init(texture: nil, color: UIColor.red, size: CGSize(width: 50, height: 50))
        isUserInteractionEnabled = true
    }

    required init?(coder aDecoder: NSCoder) {
        fatalError("init(coder:) has not been implemented")
    }

    ...

    override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
        print("touch!")
    }

}

Answer 6

实施触摸开始时调用的touchesBegan方法。或者，您也可以在touchesEnded中执行此操作。

override func touchesBegan(touches: NSSet, withEvent event: UIEvent)
{
    let touch = touches.anyObject() as UITouch
    let location = touch.locationInNode(self)
    let nodes = self.nodesAtPoint(location)

    for node in nodes
    {
        if node.name == "youNodeName"
        {
            // Node tapped
            // Do something

            break
        }
    }
}

Answer 7

使用这段代码检测SKSpriteNode上的触摸

if(nodeAtPoint(location) == node){



}

Answer 8

Swift 3.0和XCode 7.3.1的更新。我有一个SKShapeNode，我已经将它导出到一个新类并将其插入到Scene中。当我想检测这个对象时，我检查如下：

override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) {

    for touch in touches {

        let location = touch.locationInNode(self)
        let nodes = self.nodesAtPoint(location)

        for node in nodes
        {
            if node is SKNodeDerivedNode
            {
                NSLog("Touch a SKNodeDerivedNode")
                break
            }
        }
    }
}

Answer 9

这是我在Swift 4中用于查找特定类型的节点是否接触的方法：

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
    guard let touch = touches.first else {
        return
    }
    let touchPosition = touch.location(in: self)
    let touchedNodes = nodes(at: touchPosition)
    for node in touchedNodes {
        if let nodoTouched = node as? YourNodeType {
            // touched!
        }
    }
}

Answer 10

如果即使子类化SKSpriteNode后，仍然没有使精灵工作，那么您很可能在初始化时忘记添加node.isUserInteractionEnabled = true！

这允许调用touchesBegan(_:with:)，因为您现在可以与节点进行交互了。

示例：

node = MySprite(texture: texture, size: size)
node.isUserInteractionEnabled = true

Answer 11

迅速5 更新

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {

        for touch in touches {
            let location = touch.location(in: self)
            let touchedNode = self.nodes(at: location)
            for node in touchedNode {
                if node.name == "play_button" {
                    startGame()
                }
            }
        }
    }

如何检测是否触摸了SKSpriteNode

11 个答案: