Question

我如何为Fibonacci系列编写Junit测试用例，使用参数化测试？

    public static int fibonnacci(int number) {
    if (number == 1 || number == 2) {
        return 1;
    }

    return fibonnacci(number - 1) + fibonnacci(number - 2);

Answer 1

尝试简单的测试，如：

public class MyClassTest {
    MyClass clazz;
    @Before
    public void setUp() throws Exception {
        clazz = new MyClass();
    }
    @Test
    public void testFibbonacciWithOneAsInput() {//write different test cases and test for edge cases, normal cases something like below.
         Assert.assertEquals(clazz.fibonnacci(1), 1);
    }
}

Answer 2

以下是Parameterized-tests

的官方文档中的示例

@RunWith(Parameterized.class)
public class FibonacciTest {
    @Parameters
    public static Collection<Object[]> data() {
        return Arrays.asList(new Object[][] {     
                 { 0, 0 }, { 1, 1 }, { 2, 1 }, { 3, 2 }, { 4, 3 }, { 5, 5 },{ 6, 8 }  
           });
    }

    private int fInput;
    private int fExpected;

    public FibonacciTest(int input, int expected) {
        fInput= input;
        fExpected= expected;
    }

    @Test
    public void test() {
        assertEquals(fExpected, Fibonacci.compute(fInput));
    }
}

Junit for fibonacci系列

2 个答案: