我正在尝试使用Java的广度优先搜索算法。考虑到10x10网格,我试图找到最后一个单元9x9(网格从0,0开始)。到达9x9时,它已遍历网格中的所有单元格。我听说BFS会给我最短的路径。但实际上它给了我最长的路径。
请建议。
编辑 - 我已经使用了这个逻辑并完成了我的游戏。如果您想参考,请查看https://play.google.com/store/apps/details?id=com.game.puzzle.game.ballmania.android
package com.example.game.bfs.alogrithm;
import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
import java.util.Queue;
public class BFS {
static class Cell {
private int x;
private int y;
private String value;
private boolean visitStatus;
public Cell(int x, int y, String value,boolean visitStatus) {
this.x = x;
this.y = y;
this.value = value;
this.visitStatus=visitStatus;
}
}
private Cell[][] board;
private List<Cell> visited = new ArrayList<Cell>();
private boolean testDone;
public void setBoard(Cell[][] board) {
this.board = board;
}
public Cell getAdjacentUnvisitedCell(Cell cell)
{
int moves[][] = { { -1, 0 }, { 0, -1 }, { 1, 0 }, { 0, 1 } };
for (int n = 0; n < 4 /* moves.length */; ++n) {
int ti = cell.x + moves[n][0];
int tj = cell.y + moves[n][1];
// System.out.println("ti,tj" + ti +"," + tj );
if (ti >= 0 && ti < board.length && tj >= 0 && tj < board[0].length) {
// System.out.println("getAdjacentUnvisitedCell : " + "[" + board[ti][tj].x + "," + board[ti][tj].y + "]" );
// System.out.println("getAdjacentUnvisitedCell : board[ti][tj].visitStatus " + board[ti][tj].visitStatus );
if(!board[ti][tj].visitStatus) {
return board[ti][tj];
}
}
}
return null;
}
public void BFSearch(Cell start, Cell end) {
// BFS uses Queue data structure
Queue<Cell> q = new LinkedList<Cell>();
q.add(start);
visited.add(start);
board[start.x][start.y].visitStatus = true;
//printNode(start);
while( !q.isEmpty() )
{
Cell c;
c = q.peek();
Cell unVisitedadjCell = getAdjacentUnvisitedCell(c);
if(!testDone){
testDone=true;
}
if ( unVisitedadjCell != null )
{ visited.add(unVisitedadjCell);
board[unVisitedadjCell.x][unVisitedadjCell.y].visitStatus = true;
printNode(unVisitedadjCell,c);
q.add(unVisitedadjCell);
}
else
{
q.remove();
}
}
visited.clear(); //Clear visited property of nodes
}
private void printNode(Cell c,Cell node) {
System.out.println("For Node " + node.x +"," + node.y + ", " + "Just Visited : " + "[" + c.x + "," + c.y + "]" );
}
public static void main(String[] args) {
Cell[][] cells = new Cell[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
cells[i][j] = new Cell(i, j, "defaultvalue",false);
}
}
BFS board = new BFS();
board.setBoard(cells);
board.BFSearch(cells[0][0], cells[1][4]);
}
}
}
For Node 0,0, Just Visited : [1,0]
For Node 0,0, Just Visited : [0,1]
For Node 1,0, Just Visited : [2,0]
For Node 1,0, Just Visited : [1,1]
For Node 0,1, Just Visited : [0,2]
For Node 2,0, Just Visited : [3,0]
For Node 2,0, Just Visited : [2,1]
For Node 1,1, Just Visited : [1,2]
For Node 0,2, Just Visited : [0,3]
For Node 3,0, Just Visited : [4,0]
For Node 3,0, Just Visited : [3,1]
For Node 2,1, Just Visited : [2,2]
For Node 1,2, Just Visited : [1,3]
For Node 0,3, Just Visited : [0,4]
For Node 4,0, Just Visited : [5,0]
For Node 4,0, Just Visited : [4,1]
For Node 3,1, Just Visited : [3,2]
For Node 2,2, Just Visited : [2,3]
For Node 1,3, Just Visited : [1,4]
For Node 0,4, Just Visited : [0,5]
For Node 5,0, Just Visited : [6,0]
For Node 5,0, Just Visited : [5,1]
For Node 4,1, Just Visited : [4,2]
For Node 3,2, Just Visited : [3,3]
For Node 2,3, Just Visited : [2,4]
For Node 1,4, Just Visited : [1,5]
For Node 0,5, Just Visited : [0,6]
For Node 6,0, Just Visited : [7,0]
For Node 6,0, Just Visited : [6,1]
For Node 5,1, Just Visited : [5,2]
For Node 4,2, Just Visited : [4,3]
For Node 3,3, Just Visited : [3,4]
For Node 2,4, Just Visited : [2,5]
For Node 1,5, Just Visited : [1,6]
For Node 0,6, Just Visited : [0,7]
For Node 7,0, Just Visited : [8,0]
For Node 7,0, Just Visited : [7,1]
For Node 6,1, Just Visited : [6,2]
For Node 5,2, Just Visited : [5,3]
For Node 4,3, Just Visited : [4,4]
For Node 3,4, Just Visited : [3,5]
For Node 2,5, Just Visited : [2,6]
For Node 1,6, Just Visited : [1,7]
For Node 0,7, Just Visited : [0,8]
For Node 8,0, Just Visited : [9,0]
For Node 8,0, Just Visited : [8,1]
For Node 7,1, Just Visited : [7,2]
For Node 6,2, Just Visited : [6,3]
For Node 5,3, Just Visited : [5,4]
For Node 4,4, Just Visited : [4,5]
For Node 3,5, Just Visited : [3,6]
For Node 2,6, Just Visited : [2,7]
For Node 1,7, Just Visited : [1,8]
For Node 0,8, Just Visited : [0,9]
For Node 9,0, Just Visited : [9,1]
For Node 8,1, Just Visited : [8,2]
For Node 7,2, Just Visited : [7,3]
For Node 6,3, Just Visited : [6,4]
For Node 5,4, Just Visited : [5,5]
For Node 4,5, Just Visited : [4,6]
For Node 3,6, Just Visited : [3,7]
For Node 2,7, Just Visited : [2,8]
For Node 1,8, Just Visited : [1,9]
For Node 9,1, Just Visited : [9,2]
For Node 8,2, Just Visited : [8,3]
For Node 7,3, Just Visited : [7,4]
For Node 6,4, Just Visited : [6,5]
For Node 5,5, Just Visited : [5,6]
For Node 4,6, Just Visited : [4,7]
For Node 3,7, Just Visited : [3,8]
For Node 2,8, Just Visited : [2,9]
For Node 9,2, Just Visited : [9,3]
For Node 8,3, Just Visited : [8,4]
For Node 7,4, Just Visited : [7,5]
For Node 6,5, Just Visited : [6,6]
For Node 5,6, Just Visited : [5,7]
For Node 4,7, Just Visited : [4,8]
For Node 3,8, Just Visited : [3,9]
For Node 9,3, Just Visited : [9,4]
For Node 8,4, Just Visited : [8,5]
For Node 7,5, Just Visited : [7,6]
For Node 6,6, Just Visited : [6,7]
For Node 5,7, Just Visited : [5,8]
For Node 4,8, Just Visited : [4,9]
For Node 9,4, Just Visited : [9,5]
For Node 8,5, Just Visited : [8,6]
For Node 7,6, Just Visited : [7,7]
For Node 6,7, Just Visited : [6,8]
For Node 5,8, Just Visited : [5,9]
For Node 9,5, Just Visited : [9,6]
For Node 8,6, Just Visited : [8,7]
For Node 7,7, Just Visited : [7,8]
For Node 6,8, Just Visited : [6,9]
For Node 9,6, Just Visited : [9,7]
For Node 8,7, Just Visited : [8,8]
For Node 7,8, Just Visited : [7,9]
For Node 9,7, Just Visited : [9,8]
For Node 8,8, Just Visited : [8,9]
For Node 9,8, Just Visited : [9,9]
访问单元格的模式。
答案 0 :(得分:3)
从头到尾追溯日志。你会发现它实际上找到了最短的路径 - 沿着网格的边缘。不幸的是,在网格中,如果你不允许通过对角线(在这种情况下BFS离开窗口,因为对角线应该有不同的权重),所有路径只有操作&#34;到右边&#34; 34; &#34; down&#34;是最短的。
你可以通过简单的逻辑看到它 - 从0到9你必须做9次移动。您有2个坐标,从(0, 0)
到(9, 9)
,您只能在1个操作中更改一个坐标,因此最短路径有9+9=18
步。追溯并看到此路径有18个步骤。类似地,任何路径从开始到结束只有操作to the right
和down
将有18个步骤,因此任何类似的路径都是最短的。决定路径本身的只是将相邻坐标放入队列的顺序。尝试以随机顺序进行。
编辑:这里是如何计算最短路径的数量。
我们以前注意到有18个操作;其中9个是to the right
,9个是down
。这些操作的顺序并不重要,因为最终您已将(9, 9)
添加到初始(0, 0)
,因此您实际到达结尾。我们如何算他们?让我们为每个操作分配一个标识符:a_1, a_2, ... a_18
。我们现在要选择其中9个操作为down
。因此,我们选择down
操作的第一个位置,我们可以通过18种方式进行操作(因为有18种操作可供选择),然后是第二种(17
方式),依此类推,直到我们&#39 ;退出down
行动。我们本可以18*17*...*10
方式完成这项工作。现在我们为right
操作选择点。我们可以9*8*...*1
方式(通过神学)这样做。但是现在我们并没有真正区分每个down
指令,对吗?我们本可以down
方式选择第一个9
操作,8
方式选择第二个right
,依此类推。同样,我们可以选择(18*17*...*1)/((9*8*...*1)*(9*8*...*1)) = 48 620
次操作。最后,我们推断出有9
种方式(我们将操作区分为无意义)。它也是您可以从18
点中选择Introductory combinatorics
的方式的数量。
如果我的解释过于混乱,我建议您Richard A. Brualdi
查看{{1}}。关于某些离散数学领域的有趣事情,这本书非常酷。它很容易阅读。
答案 1 :(得分:1)
根据我对其他答案的理解(这是lared),你的代码可能是这样的:
package com.example.game.bfs.alogrithm;
import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
import java.util.Queue;
/**
http://stackoverflow.com/questions/27768394/breadth-first-search-is-not-returning-the-shortest-path
**/
public class BFS {
static class Cell {
private int x;
private int y;
private String value;
private boolean visitStatus;
private Cell previousCell;
public Cell(int x, int y, String value,boolean visitStatus) {
this.x = x;
this.y = y;
this.value = value;
this.visitStatus=visitStatus;
}
public String toString()
{
return "[" + x + "," + y + "]";
}
}
private Cell[][] board;
private List<Cell> visited = new ArrayList<Cell>();
private boolean testDone;
public void setBoard(Cell[][] board) {
this.board = board;
}
public Cell getAdjacentUnvisitedCell(Cell cell)
{
int moves[][] = { { -1, 0 }, { 0, -1 }, { 1, 0 }, { 0, 1 } };
// for diagonal moves :
// int moves[][] = { { -1, 0 }, { 0, -1 }, { 1, 0 }, { 0, 1 }, {1,1} };
for (int n = 0; n < moves.length ; ++n) {
int ti = cell.x + moves[n][0];
int tj = cell.y + moves[n][1];
// System.out.println("ti,tj" + ti +"," + tj );
if (ti >= 0 && ti < board.length && tj >= 0 && tj < board[0].length) {
// System.out.println("getAdjacentUnvisitedCell : " + "[" + board[ti][tj].x + "," + board[ti][tj].y + "]" );
// System.out.println("getAdjacentUnvisitedCell : board[ti][tj].visitStatus " + board[ti][tj].visitStatus );
if(!board[ti][tj].visitStatus) {
return board[ti][tj];
}
}
}
return null;
}
public void BFSearch(Cell start, Cell end) {
// BFS uses Queue data structure
Queue<Cell> q = new LinkedList<Cell>();
Cell unVisitedadjCell = start;
Cell c = null;
q.add(start);
visited.add(start);
board[start.x][start.y].visitStatus = true;
//printNode(start);
while( !q.isEmpty() )
{
c = q.peek();
unVisitedadjCell = getAdjacentUnvisitedCell(c);
if(!testDone){
testDone=true;
}
if ( unVisitedadjCell != null )
{ visited.add(unVisitedadjCell);
board[unVisitedadjCell.x][unVisitedadjCell.y].visitStatus = true;
printNode(unVisitedadjCell,c);
unVisitedadjCell.previousCell=c;
q.add(unVisitedadjCell);
}
else
{
q.remove();
}
}
System.out.println("Shortest path");
while ( ( c != null ) && ( c!=start))
{
printNode(c.previousCell,c);
c = c.previousCell;
}
visited.clear(); //Clear visited property of nodes
}
private void printNode(Cell c,Cell node) {
System.out.println("For Node " + node.x +"," + node.y + ", " + "Just Visited : " + c + " previous was " + node.previousCell);
}
public static void main(String[] args) {
Cell[][] cells = new Cell[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
cells[i][j] = new Cell(i, j, "defaultvalue",false);
}
}
cells[0][1].value = "B";
cells[0][2].value = "B";
cells[1][1].value = "B";
cells[1][3].value = "B";
cells[2][1].value = "B";
cells[2][2].value = "B";
cells[2][3].value = "B";
cells[2][7].value = "B";
cells[2][8].value = "B";
BFS board = new BFS();
board.setBoard(cells);
board.BFSearch(cells[0][0], cells[1][4]);
}
}
java -cp。 com.example.game.bfs.alogrithm.BFS
For Node 0,0, Just Visited : [1,0] previous was null
For Node 0,0, Just Visited : [0,1] previous was null
For Node 1,0, Just Visited : [2,0] previous was [0,0]
For Node 1,0, Just Visited : [1,1] previous was [0,0]
For Node 0,1, Just Visited : [0,2] previous was [0,0]
For Node 2,0, Just Visited : [3,0] previous was [1,0]
For Node 2,0, Just Visited : [2,1] previous was [1,0]
For Node 1,1, Just Visited : [1,2] previous was [1,0]
For Node 0,2, Just Visited : [0,3] previous was [0,1]
For Node 3,0, Just Visited : [4,0] previous was [2,0]
For Node 3,0, Just Visited : [3,1] previous was [2,0]
For Node 2,1, Just Visited : [2,2] previous was [2,0]
For Node 1,2, Just Visited : [1,3] previous was [1,1]
For Node 0,3, Just Visited : [0,4] previous was [0,2]
For Node 4,0, Just Visited : [5,0] previous was [3,0]
For Node 4,0, Just Visited : [4,1] previous was [3,0]
For Node 3,1, Just Visited : [3,2] previous was [3,0]
For Node 2,2, Just Visited : [2,3] previous was [2,1]
For Node 1,3, Just Visited : [1,4] previous was [1,2]
For Node 0,4, Just Visited : [0,5] previous was [0,3]
For Node 5,0, Just Visited : [6,0] previous was [4,0]
For Node 5,0, Just Visited : [5,1] previous was [4,0]
For Node 4,1, Just Visited : [4,2] previous was [4,0]
For Node 3,2, Just Visited : [3,3] previous was [3,1]
For Node 2,3, Just Visited : [2,4] previous was [2,2]
For Node 1,4, Just Visited : [1,5] previous was [1,3]
For Node 0,5, Just Visited : [0,6] previous was [0,4]
For Node 6,0, Just Visited : [7,0] previous was [5,0]
For Node 6,0, Just Visited : [6,1] previous was [5,0]
For Node 5,1, Just Visited : [5,2] previous was [5,0]
For Node 4,2, Just Visited : [4,3] previous was [4,1]
For Node 3,3, Just Visited : [3,4] previous was [3,2]
For Node 2,4, Just Visited : [2,5] previous was [2,3]
For Node 1,5, Just Visited : [1,6] previous was [1,4]
For Node 0,6, Just Visited : [0,7] previous was [0,5]
For Node 7,0, Just Visited : [8,0] previous was [6,0]
For Node 7,0, Just Visited : [7,1] previous was [6,0]
For Node 6,1, Just Visited : [6,2] previous was [6,0]
For Node 5,2, Just Visited : [5,3] previous was [5,1]
For Node 4,3, Just Visited : [4,4] previous was [4,2]
For Node 3,4, Just Visited : [3,5] previous was [3,3]
For Node 2,5, Just Visited : [2,6] previous was [2,4]
For Node 1,6, Just Visited : [1,7] previous was [1,5]
For Node 0,7, Just Visited : [0,8] previous was [0,6]
For Node 8,0, Just Visited : [9,0] previous was [7,0]
For Node 8,0, Just Visited : [8,1] previous was [7,0]
For Node 7,1, Just Visited : [7,2] previous was [7,0]
For Node 6,2, Just Visited : [6,3] previous was [6,1]
For Node 5,3, Just Visited : [5,4] previous was [5,2]
For Node 4,4, Just Visited : [4,5] previous was [4,3]
For Node 3,5, Just Visited : [3,6] previous was [3,4]
For Node 2,6, Just Visited : [2,7] previous was [2,5]
For Node 1,7, Just Visited : [1,8] previous was [1,6]
For Node 0,8, Just Visited : [0,9] previous was [0,7]
For Node 9,0, Just Visited : [9,1] previous was [8,0]
For Node 8,1, Just Visited : [8,2] previous was [8,0]
For Node 7,2, Just Visited : [7,3] previous was [7,1]
For Node 6,3, Just Visited : [6,4] previous was [6,2]
For Node 5,4, Just Visited : [5,5] previous was [5,3]
For Node 4,5, Just Visited : [4,6] previous was [4,4]
For Node 3,6, Just Visited : [3,7] previous was [3,5]
For Node 2,7, Just Visited : [2,8] previous was [2,6]
For Node 1,8, Just Visited : [1,9] previous was [1,7]
For Node 9,1, Just Visited : [9,2] previous was [9,0]
For Node 8,2, Just Visited : [8,3] previous was [8,1]
For Node 7,3, Just Visited : [7,4] previous was [7,2]
For Node 6,4, Just Visited : [6,5] previous was [6,3]
For Node 5,5, Just Visited : [5,6] previous was [5,4]
For Node 4,6, Just Visited : [4,7] previous was [4,5]
For Node 3,7, Just Visited : [3,8] previous was [3,6]
For Node 2,8, Just Visited : [2,9] previous was [2,7]
For Node 9,2, Just Visited : [9,3] previous was [9,1]
For Node 8,3, Just Visited : [8,4] previous was [8,2]
For Node 7,4, Just Visited : [7,5] previous was [7,3]
For Node 6,5, Just Visited : [6,6] previous was [6,4]
For Node 5,6, Just Visited : [5,7] previous was [5,5]
For Node 4,7, Just Visited : [4,8] previous was [4,6]
For Node 3,8, Just Visited : [3,9] previous was [3,7]
For Node 9,3, Just Visited : [9,4] previous was [9,2]
For Node 8,4, Just Visited : [8,5] previous was [8,3]
For Node 7,5, Just Visited : [7,6] previous was [7,4]
For Node 6,6, Just Visited : [6,7] previous was [6,5]
For Node 5,7, Just Visited : [5,8] previous was [5,6]
For Node 4,8, Just Visited : [4,9] previous was [4,7]
For Node 9,4, Just Visited : [9,5] previous was [9,3]
For Node 8,5, Just Visited : [8,6] previous was [8,4]
For Node 7,6, Just Visited : [7,7] previous was [7,5]
For Node 6,7, Just Visited : [6,8] previous was [6,6]
For Node 5,8, Just Visited : [5,9] previous was [5,7]
For Node 9,5, Just Visited : [9,6] previous was [9,4]
For Node 8,6, Just Visited : [8,7] previous was [8,5]
For Node 7,7, Just Visited : [7,8] previous was [7,6]
For Node 6,8, Just Visited : [6,9] previous was [6,7]
For Node 9,6, Just Visited : [9,7] previous was [9,5]
For Node 8,7, Just Visited : [8,8] previous was [8,6]
For Node 7,8, Just Visited : [7,9] previous was [7,7]
For Node 9,7, Just Visited : [9,8] previous was [9,6]
For Node 8,8, Just Visited : [8,9] previous was [8,7]
For Node 9,8, Just Visited : [9,9] previous was [9,7]
Shortest path
For Node 9,9, Just Visited : [9,8] previous was [9,8]
For Node 9,8, Just Visited : [9,7] previous was [9,7]
For Node 9,7, Just Visited : [9,6] previous was [9,6]
For Node 9,6, Just Visited : [9,5] previous was [9,5]
For Node 9,5, Just Visited : [9,4] previous was [9,4]
For Node 9,4, Just Visited : [9,3] previous was [9,3]
For Node 9,3, Just Visited : [9,2] previous was [9,2]
For Node 9,2, Just Visited : [9,1] previous was [9,1]
For Node 9,1, Just Visited : [9,0] previous was [9,0]
For Node 9,0, Just Visited : [8,0] previous was [8,0]
For Node 8,0, Just Visited : [7,0] previous was [7,0]
For Node 7,0, Just Visited : [6,0] previous was [6,0]
For Node 6,0, Just Visited : [5,0] previous was [5,0]
For Node 5,0, Just Visited : [4,0] previous was [4,0]
For Node 4,0, Just Visited : [3,0] previous was [3,0]
For Node 3,0, Just Visited : [2,0] previous was [2,0]
For Node 2,0, Just Visited : [1,0] previous was [1,0]
For Node 1,0, Just Visited : [0,0] previous was [0,0]
然后尝试使用带有对角线的注释代码......