Question

我在使用TinyGPS库解析Lat和Lon时遇到了麻烦。这个库是否与RFduino兼容？我可以通过向RFduino加载空白草图然后打开串行监视器来读取NMEA字符串，因此我知道GPS数据正在通过串行端口，但是当我尝试将Lat或Lon变为变量时，它用999999999填充变量。我通过BLE将这些数据发送到android。如果我不尝试获取GPS数据，我可以在lat或lon变量中发送我想要的任何值，它出现在我的自定义Android应用程序中。我在某处读到软件库对rfduino不起作用。这是真的？如果没有，我将能够通过硬串口打印我的数据，使故障排除更容易。下面我附上了我在RFduino上使用的代码。任何建议将不胜感激。

    //       CODE         //

#include <RFduinoBLE.h>
#include <TinyGPS.h>


TinyGPS gps;

long lat = 5; //Load lat/lon with junk value for testing
long lon = 6;
char latBuf[20];
char lonBuf[20];

void setup() {
  // this is the data we want to appear in the advertisement
  // (if the deviceName and advertisementData are too long to fix into the 31 byte
  // ble advertisement packet, then the advertisementData is truncated first down to
  // a single byte, then it will truncate the deviceName)
  RFduinoBLE.advertisementData = "ledbtn";

  // start the BLE stack
  RFduinoBLE.begin();
  Serial.begin(9600);//For GPS Communication
}



void loop(){
    char c = byte(Serial.read());
    gps.encode(c);
    gps.get_position(&lat,&lon); // get latitude and longitude
    // send position as char[]

    String latString = String(lat);
    String lonString = String(lon);

    latString.toCharArray(latBuf, 20);
    lonString.toCharArray(lonBuf, 20);    
    RFduinoBLE.send(lonBuf, 20);
  }


void RFduinoBLE_onDisconnect()
{
}

void RFduinoBLE_onReceive(char *data, int len)
{
  RFduinoBLE.send(lonBuf, 20);
}

Answer 1

我看到一个问题：loop（）试图在每次循环执行时读出GPS坐标。这种方法有两个问题：1）循环不会等到串行数据就绪，2）循环不等到接收的GPS数据有效。

从阅读http://arduino.cc/en/Tutorial/ReadASCIIString和http://arduiniana.org/libraries/tinygps/我建议将loop（）重写为以下内容：

loop() {
  char c;
  float fLat, fLon;
  unsigned long fix_age;
  static unsigned long previous_fix_age = 0;

  // If nothing to read; do nothing.
  // Read as many characters as are available.
  while (Serial.available() > 0) {

    // Tell the GPS library about the new character.
    c = Serial.read();
    gps.encode(c);

    gps.f_get_position(&flat, &flon, &fix_age);
    if (fix_age != TinyGPS::GPS_INVALID_AGE && fix_age != previous_fix_age) {
      // new GPS data is valid, new, and ready to be printed

      previous_fix_age = fix_age; // remember that we've reported this data.

      String latString = String(lat);
      ...the rest of the code you already have to print the lat and lon.
    }

  }
}

有关previous_fix_age的代码在那里，只有当从GPS收到新的修复时，循环才会打印坐标。

RFduino没有从GPS中拉出NMEA字符串

1 个答案: