C ++ TicTacToe问题

Question

我正在努力学习C ++并且我已经制作了小型的tictactoe游戏，但有些事情是错误的。我试图让胜利者无论是虚空还是布尔。但是当我键入一个坐标时，它会预先形成类。为了简单起见，你只能赢得如果3在上面是O.什么是错的？ 所以如果我输入：0 0它说胜利者

以下是代码：

#include <iostream>

const int rows = 3;
const int elements = 3;

const char Ochar = 'O';

char board[rows][elements];

void Clear()
{
    for (int i = 0; i < rows; i++)
    {
        for (int j = 0; j < elements; j++)
        {
            board[i][j] = 0;
        }
    }
}

void Show()
{
    for (int i = 0; i < rows; i++)
    {
        for (int j = 0; j < elements; j++)
        {
            std::cout << " " << board[i][j] << " |";
        }
        std::cout << std::endl;
        std::cout << "------------" << std::endl;
    }
}

bool PlayerAttack(int x, int y)
{
    if (board[x][y] == 0)
    {
        board[x][y] = Ochar;
        return true;
    }
    return false;
}

void Winner()
{
    if (board[0][0], board[0][1], board[0][2] = 'O')
    {
        std::cout << "Winner";
    }
}

int main()
{
    Clear();
    Show();
    int pos1 = 0;
    int pos2 = 0;
    while (1)
    {
        std::cout << "Please input a coordinate: "; std::cin >> pos1 >> pos2; std::cout <<     std::endl;
        PlayerAttack(pos1, pos2);
        Show();
        Winner();
    }
}

Answer 1

此行不符合您的想法

if (board[0][0], board[0][1], board[0][2] = 'O')

你必须这样做

if (board[0][0] == 'O' && board[0][1] == 'O' && board[0][2] == 'O')

使用Winner功能打破循环

bool Winner()
{
    // You'll obviously have to check more than just this row
    if (board[0][0] == 'O' && board[0][1] == 'O' && board[0][2] == 'O')
    {
        std::cout << "Winner";
        return true;
    }
    return false;
}

然后在main

int main()
{
    Clear();
    Show();
    int pos1 = 0;
    int pos2 = 0;
    bool winner = false;
    while (!winner)
    {
        std::cout << "Please input a coordinate: "; std::cin >> pos1 >> pos2; std::cout <<     std::endl;
        PlayerAttack(pos1, pos2);
        Show();
        winner = Winner(); // Use the returned bool
    }
}