只想询问此代码广告的工作原理。我只是想澄清一些代码行。
我只是想基本上要显示＆＃39; O＆＃39;在每个＆＃39; X＆＃39;之后我把这个基本的tictactoe游戏放在索引中。但是当我这样做时，我会遇到一些像无限循环这样的错误，限制整个程序运行。请帮我。谢谢。
这是我的功能代码。
int InputComHard() {
int num, ctr = 0,temp = 1;
if (field == 'X') {
cout << "Choose your field [Player X (1~9)]";
cin >> num;
} else {
cout << "Choose your field [Player O (1~9) ]";
for(int x = 0; x < 3;x++){
for(int y = 0;y<3;y++){
temp++;
if(tic[x][y] =='X'&&tic[x][y+1]!='X'){
num = temp;
}
}
}
}
//Here's the condition where the 'X' or 'O' will be placed on the entire
matrix.
if (num == 1 && tic[0][0] == NULL)
tic[0][0] = field;
else if (num == 2 && tic[0][1] == NULL)
tic[0][1] = field;
else if (num == 3 && tic[0][2] == NULL)
tic[0][2] = field;
else if (num == 4 && tic[1][0] == NULL)
tic[1][0] = field;
else if (num == 5 && tic[1][1] == NULL)
tic[1][1] = field;
else if (num == 6 && tic[1][2] == NULL)
tic[1][2] = field;
else if (num == 7 && tic[2][0] == NULL)
tic[2][0] = field;
else if (num == 8 && tic[2][1] == NULL)
tic[2][1] = field;
else if (num == 9 && tic[2][2] == NULL)
tic[2][2] = field;
else {
ctr++;
}
return ctr;
}
当我输入1时，＆＃39; X＆＃39;出现在索引[0] [0]然后，＆＃39; O＆＃39;同时出现在[0] [1]，之后，当我输入3时，错误开始，发生无限循环。我只想基本上对我的计划做的是显示＆＃39; O＆＃39;对于每个＆＃39; X＆＃39;我进入并将被放置在它旁边。请帮忙
here is my main
#include<iostream>
#include<stdlib.h>
using namespace std;
char tic[3][3];
char field = 'X';
void Draw() {
//system("CLS");
cout << "\n\n\tTic Tac Toe\n\n";
cout << "Player 1 (X) - Player 2 (O)" << endl << endl;
cout << endl;
//Displays the Matrix(rows and columns)
cout << " | | " << endl;
cout << " " << tic[0][0] << " | " << tic[0][1] << " | " << tic[0][2] << endl;
cout << "_____|_____|_____" << endl;
cout << " | | " << endl;
cout << " " << tic[1][0] << " | " << tic[1][1] << " | " << tic[1][2] << endl;
cout << "_____|_____|_____" << endl;
cout << " | | " << endl;
cout << " " << tic[2][0] << " | " << tic[2][1] << " | " << tic[2][2] << endl;
cout << " | | " << endl << endl;
}
void Turn() {
if (field == 'X')
field = 'O';
else
field = 'X';
}
//Function to determine the winner based on the array positions.
char Winner() {
int ctr = 0;
if (tic[0][0] == 'X' && tic[0][1] == 'X' && tic[0][2] == 'X')
return 'X';
if (tic[1][0] == 'X' && tic[1][1] == 'X' && tic[1][2] == 'X')
return 'X';
if (tic[2][0] == 'X' && tic[2][1] == 'X' && tic[2][2] == 'X')
return 'X';
if (tic[0][0] == 'X' && tic[1][0] == 'X' && tic[2][0] == 'X')
return 'X';
if (tic[0][1] == 'X' && tic[1][1] == 'X' && tic[2][1] == 'X')
return 'X';
if (tic[0][2] == 'X' && tic[1][2] == 'X' && tic[2][2] == 'X')
return 'X';
if (tic[0][0] == 'X' && tic[1][1] == 'X' && tic[2][2] == 'X')
return 'X';
if (tic[2][0] == 'X' && tic[1][1] == 'X' && tic[0][2] == 'X')
return 'X';
//second player
if (tic[0][0] == 'O' && tic[0][1] == 'O' && tic[0][2] == 'O')
return 'O';
if (tic[1][0] == 'O' && tic[1][1] == 'O' && tic[1][2] == 'O')
return 'O';
if (tic[2][0] == 'O' && tic[2][1] == 'O' && tic[2][2] == 'O')
return 'O';
if (tic[0][0] == 'O' && tic[1][0] == 'O' && tic[2][0] == 'O')
return 'O';
if (tic[0][1] == 'O' && tic[1][1] == 'O' && tic[2][1] == 'O')
return 'O';
if (tic[0][2] == 'O' && tic[1][2] == 'O' && tic[2][2] == 'O')
return 'O';
if (tic[0][0] == 'O' && tic[1][1] == 'O' && tic[2][2] == 'O')
return 'O';
if (tic[2][0] == 'O' && tic[1][1] == 'O' && tic[0][2] == 'O')
return 'O';
for (int x = 0; x < 3; x++) {
for (int y = 0; y < 3; y++) {
if (tic[x][y] == 'X' || tic[x][y] == 'O') {
ctr++;
}
}
if (ctr == 9) {
return 'D';
}
}
}
int main()
{
int choice;
cout << "Choose Mode: \n";
cout << "Player VS Player [1]\n";
cout << "Player VS BOT(EASY) [2]\n";
cout << "Player VS BOT(UNFAIR!) [3]\n";
cin >> choice;
switch (choice) {
case 1:
system("CLS");
Draw();
while (1) {
if (Input() == 1) {
system("CLS");
cout << "Occupied!\n";
} else {
system("CLS");
Turn();
}
Draw();
if (Winner() == 'X') {
cout << "X wins!" << endl;
break;
} else if (Winner() == 'O') {
cout << "O wins!" << endl;
break;
} else if (Winner() == 'D') {
cout << "DRAW!" << endl;
break;
}
}
break;
case 2:
system("CLS");
Draw();
while (1) {
if (InputCom() == 1) {
system("CLS");
cout << "Occupied!\n";
} else {
system("CLS");
Turn();
}
Draw();
if (Winner() == 'X') {
cout << "X wins!" << endl;
break;
} else if (Winner() == 'O') {
cout << "O wins!" << endl;
break;
} else if (Winner() == 'D') {
cout << "DRAW!" << endl;
break;
}
}
break;;
case 3:
system("CLS");
Draw();
while (1) {
if (InputComHard() == 1) {
system("CLS");
cout << "Occupied!\n";
} else {
system("CLS");
Turn();
}
Draw();
if (Winner() == 'X') {
cout << "X wins!" << endl;
break;
} else if (Winner() == 'O') {
cout << "O wins!" << endl;
break;
} else if (Winner() == 'D') {
cout << "DRAW!" << endl;
break;
}
}
break;
default:
cout << "Invalid Input!" << endl;
}
system("pause");
}
答案 0 :(得分：0)
它有点难以阅读代码，但我可以看到一个相当明显的问题会导致无限循环：当你的机器人转向InputComHard()时，它会选择相同的（占用的）广场每一次。当您从main()拨打电话时，您会收到一个1，表示占用的广场，但您只需再次拨打它。你需要某种方法告诉它选择一些尚未尝试的方格。
或者更好的是，更改InputComHard()，使其在成功选择可用的方格之前不会返回。
另外，在InputComHard()中，您在未初始化的情况下声明num。当你的机器人转弯时，如果你永远不满足条件if(tic[x][y] =='X'&&tic[x][y+1]!='X')，那么你永远不会到达num = temp，而num最终会得到一个垃圾值。这可能会给你带来一些麻烦，也许是循环，或许其他东西更糟糕。