TTT（TicTacToe）C ++

Question

我想写一个包含2名玩家的TicTacToe程序（我正在从Jumping into C++进行练习）。下面的语法没有任何错误，但是假设我输入1或2，程序只是退出而没有任何错误或任何结果。这是我想出的代码：

#include <iostream>
using namespace std;


int board_pos;



int main()
{
cout << "Enter => 1 for X; 2 for O:" << endl;

enum TTT_Board{topLeft, topMid, topRight, middleLeft, middleMid, middleRight, botLeft, botMid, botRight};
cout << "-------" << endl;

cout << "|" << topLeft << "|" << topMid << "|" << topRight << "|" << endl; /* Top cells of the board */

cout << "-------" << endl;

cout << "|" << middleLeft << "|" << middleMid << "|" << middleRight << "|" << endl;

cout << "-------" << endl;

cout << "|" << botLeft << "|" << botMid << "|" << botRight << "|" << endl;

cout << "-------" << endl;

if (board_pos == 0){
    switch (board_pos) {
        case topLeft:
            cout << " " << endl;
            break;
        case topMid:
            cout << " " << endl;
            break;
        case topRight:
            cout << " " << endl;
            break;
        case middleLeft:
            cout << " " << endl;
            break;
        case middleMid:
            cout << " " << endl;
            break;
        case middleRight:
            cout << " " << endl;
            break;
        case botLeft:
            cout << " " << endl;
            break;
        case botMid:
            cout << " " << endl;
            break;
        case botRight:
            cout << " " << endl;
            break;


        default:
            break;
    }

}
else if (board_pos == 1)
{
    switch (board_pos) {
        case topLeft:
            cout << "X" << endl;
            break;
        case topMid:
            cout << "X" << endl;
            break;
        case topRight:
            cout << "X" << endl;
            break;
        case middleLeft:
            cout << "X" << endl;
            break;
        case middleMid:
            cout << "X" << endl;
            break;
        case middleRight:
            cout << "X" << endl;
            break;
        case botLeft:
            cout << "X" << endl;
            break;
        case botMid:
            cout << "X" << endl;
            break;
        case botRight:
            cout << "X" << endl;
            break;


        default:
            break;
    }
}
else if (board_pos == 2)
{
    switch (board_pos) {
        case topLeft:
            cout << "O" << endl;
            break;
        case topMid:
            cout << "O" << endl;
            break;
        case topRight:
            cout << "O" << endl;
            break;
        case middleLeft:
            cout << "O" << endl;
            break;
        case middleMid:
            cout << "O" << endl;
            break;
        case middleRight:
            cout << "O" << endl;
            break;
        case botLeft:
            cout << "O" << endl;
            break;
        case botMid:
            cout << "O" << endl;
            break;
        case botRight:
            cout << "O" << endl;
            break;


        default:
            break;
    }
}
else {
    cout << "Please enter: 1 for X, 2 for O, and 0 if you want you skip the cell";

}
cin >> board_pos;


}

注意：程序确实编译了！

Answer 1

您应该将所有逻辑代码提取到单独的函数中，然后在cin中的while循环中执行main()，当用户输入非数字时退出。< / p>

你不应该递归地调用main。

Answer 2

您递归调用main()。

标准规定：

3.6.1.3

  

＆＃34;函数main不得在程序中使用。＆＃34;

5.2.2.9

  

＆＃34;允许递归调用，但名为main＆＃34;

的函数除外

在您对main()的递归调用后，您正在阅读用户输入，如果此调用成功，将无法让您的用户输入任何内容。

编译的程序不一定是好的程序。