Question

我遇到了问题，我想总结一下我的结果列，这是我的代码：

SELECT 
    [study_service]
    ,DATEDIFF(minute,[study_date_arrivee],[study_date_patient_prepared]) as [Time-ARRIVED-PREPARED]
    ,DATEDIFF(minute,[study_date_arrivee],[study_date_start]) as [Time-ARRIVED-START] 
    ,DATEDIFF(minute,[study_date_start],[study_date_dossier_pret]) as [Time-START-DOSSPRET]
    ,DATEDIFF(minute,[study_date_dossier_pret],[study_date_remise_resultat]) as [Time-DOSSPRET-DOSSREMIS]
FROM 
    [VisionTST].[dbo].[PremierTrimestre]

我希望最终结果如下：

Total of `[Time-ARRIVED-PREPARED]`,`[Time-ARRIVED-Start]`,...

Answer 1

SELECT 
  [study_service]
  ,sum(DATEDIFF(minute,[study_date_arrivee],[study_date_patient_prepared])) as [Time-ARRIVED-PREPARED]
  ,sum(DATEDIFF(minute,[study_date_arrivee],[study_date_start])) as [Time-ARRIVED-START]
  ,sum(DATEDIFF(minute,[study_date_start],[study_date_dossier_pret])) as [Time-START-DOSSPRET]
  ,sum(DATEDIFF(minute,[study_date_dossier_pret],[study_date_remise_resultat])) as [Time-DOSSPRET-    DOSSREMIS]

FROM [VisionTST].[dbo].[PremierTrimestre]

如何在sql server中汇总结果列

1 个答案: