Question

例如，有以下数据：

如何将a和b加在一起，c和d得到这样的结果？

ab 24
cd 35

Answer 1

select sum(case when col1 in ('a','b') then col2 end) as ab_sum,
       sum(case when col1 in ('c','d') then col2 end) as cd_sum
from your_table

Answer 2

这也可以帮到你，

DECLARE @TAB TABLE(NAME VARCHAR(1), MARK INT)
INSERT INTO @TAB VALUES 
('A',10),
('B', 5),
('C',15),
('D', 2),
('A', 3),
('B', 6),
('C', 8),
('D',10)

SELECT  NAME,SUM(MARK) 
FROM    (
        SELECT  CASE WHEN NAME IN ('A','B') THEN 'AB' WHEN NAME IN ('C','D') THEN 'CD' END NAME,
                MARK 
        FROM @TAB A 
        ) LU
GROUP   BY NAME

Answer 3

尝试：

select 
    'ab' col1, 
    SUM(col2) col2 
from tbl 
where col1 in ('a', 'b')
union
select 
    'cd', 
    SUM(col2) 
from tbl 
where col1 in ('c', 'd')

Answer 4

对我来说似乎是一个很好的机会：

| CODE_RANGE | RANGE_VALUE |
|------------|-------------|
|         ab |          24 |
|         cd |          35 |

SELECT
      CASE
            WHEN code BETWEEN 'a' AND 'b' THEN 'ab'
            WHEN code BETWEEN 'c' AND 'd' THEN 'cd' END AS code_range
    , SUM(value)                                        AS range_value
FROM Table1
GROUP BY
      CASE
            WHEN code BETWEEN 'a' AND 'b' THEN 'ab'
            WHEN code BETWEEN 'c' AND 'd' THEN 'cd' END

请参阅：http://sqlfiddle.com/#!3/a6b7e3/1

Answer 5

SELECT
  (CASE col1 
  WHEN 'a' THEN 'ab'
  WHEN 'b' THEN 'ab'
  WHEN 'c' THEN 'cd'
  WHEN 'd' THEN 'cd' 
  END) x,
  SUM(col2) y
FROM tbl
GROUP BY (CASE col1 
  WHEN 'a' THEN 'ab'
  WHEN 'b' THEN 'ab'
  WHEN 'c' THEN 'cd'
  WHEN 'd' THEN 'cd' 
  END)

如何在列中汇总列出的值

5 个答案: