Question

我正在为一个tic tac toe游戏编写一个c ++程序。游戏必须有一个胜利数量的游戏计数器每个球员都有多少关系。问题我的意思是我似乎无法让董事会明白，所以当它到达一场比赛结束时，董事会会清除 X＆O和X。我能得到任何帮助，我将非常感激！

#include <iostream>

using namespace std;

void display_board();
void player_turn();
bool gameover();
int xwins, owins, ties;

char turn;
bool draw = false;
char board[3][3] = {{'1', '2', '3'}, {'4', '5', '6'}, {'7', '8', '9'}};

int main()
{
    cout << "Tic Tac Toe Game\n";
    cout << "Player 1 [X] --- Player 2 [O]\n";
    turn = 'X';
    char board[3][3] = {{'1', '2', '3'}, {'4', '5', '6'}, {'7', '8', '9'}};

    while (!gameover())
    {
        display_board();
        player_turn();
        gameover();
    }

    if (turn == 'O' && !draw)
    {
        display_board();
        cout << endl << endl << "Player 1 [X] Wins! Game Over!\n";
        xwins++;
    }
    else if (turn == 'X' && !draw)
    {
        display_board();
        cout << endl << endl << "Player 2 [O] Wins! Game Over!\n";
        owins++;
    }
    else
    {
        display_board();
        cout << endl << endl << "It's a draw! Game Over!\n";
        ties++;
    }


}

void display_board()
{
    cout << "---------------------" << endl << endl;
    cout << "     |     |     " << endl;
    cout << "  " << board[0][0] << "  |  " << board[0][1] << "  |  " << board[0][2] <<"      Player 1 wins "<<xwins<< endl;
    cout << "_____|_____|_____" <<endl;
    cout << "     |     |     " << endl;
    cout << "  " << board[1][0] << "  |  " << board[1][1] << "  |  " << board[1][2] <<"      Player 2 wins "<<owins<< endl;
    cout << "_____|_____|_____" << endl;
    cout << "     |     |     " << endl;
    cout << "  " << board[2][0] << "  |  " << board[2][1] << "  |  " << board[2][2] <<"      Ties "<<ties<< endl;
    cout << "     |     |     " << endl;
}

void player_turn()
{
    int choice;
    int row = 0, column = 0;

    if (turn == 'X')
    {
        cout << "Player 1 turn [X]: ";
    }
    else if (turn == 'O')
    {
        cout << "Player 2 turn [O]: ";
    }
    cin >> choice;

    switch (choice)
    {
    case 1: row = 0; column = 0; break;
    case 2: row = 0; column = 1; break;
    case 3: row = 0; column = 2; break;
    case 4: row = 1; column = 0; break;
    case 5: row = 1; column = 1; break;
    case 6: row = 1; column = 2; break;
    case 7: row = 2; column = 0; break;
    case 8: row = 2; column = 1; break;
    case 9: row = 2; column = 2; break;
    default:
        cout << "You didn't enter a correct number! Try again\n";
        player_turn();
    }

    if (turn == 'X' && board[row][column] != 'X' && board[row][column] != 'O')
    {
        board[row][column] = 'X';
        turn = 'O';
    }
    else if (turn == 'O' && board[row][column] != 'X' && board[row][column] != 'O')
    {
        board[row][column] = 'O';
        turn = 'X';
    }
    else
    {
        cout << "The cell you chose is used! Try again\n";
        player_turn();
    }

}

bool gameover()
{
    for (int i = 0; i < 3; i++)//Check for a win
    {
        if ((board[i][0] == board[i][1] && board[i][1] == board[i][2]) || (board[0][i] == board[1][i] && board[1][i] == board[2][i]) || (board[0][0] == board[1][1] && board[1][1] == board[2][2]) || (board[0][2] == board[1][1] && board[1][1] == board[2][0]))
        {
            return true;
        }
    }

    for (int i = 0; i < 3; i++)//Check for draw
    {
        for (int j = 0; j < 3; j++)
        {
            if (board[i][j] != 'X' && board[i][j] != 'O')
            {
                return false;
            }
        }
    }
    draw = true;
    return true;
}

Answer 1

我可以看到您的代码存在一些问题：

while (!gameover())
{
    display_board();
    player_turn();
    gameover();
}

你不需要循环内的gameover（）。你已经在条件下检查了它。

此外，您不会在每个游戏实例后重置全局变量。添加另一个while / do-while循环，该循环一直运行到特定条件。在此循环中，添加您的主要功能。并为每个循环实例重置全局变量（绘图，板和转）。

Answer 2

试试这个

do{
    cin >> choice;

    switch (choice)
    {
        case 1: row = 0; column = 0; break;
        case 2: row = 0; column = 1; break;
        case 3: row = 0; column = 2; break;
        case 4: row = 1; column = 0; break;
        case 5: row = 1; column = 1; break;
        case 6: row = 1; column = 2; break;
        case 7: row = 2; column = 0; break;
        case 8: row = 2; column = 1; break;
        case 9: row = 2; column = 2; break;
        default:
        cout << "You didn't enter a correct number! Try again\n";
    }
}
while(choice<1 || choice>9);

因为如果用户输入其再次调用player_turn();的任何其他值，那么它将工作recursively（在函数内调用相同的函数）。

在检查gameover();时，无需再次在循环内调用while(!gameover())。

在绘制匹配后，您需要设置值，如果数组为1,2,3 ...并调用函数display_board();。

Answer 3

如果我已正确理解您的问题，那么有两个问题：

1）你需要找到一个胜利和领带计数器的地方。

bool gameover()
{
    for (int i = 0; i < 3; i++)//Check for a win
    {
        bool row_match    = (board[i][0] == board[i][1] && board[i][1] == board[i][2]);
        bool column_match = (board[0][i] == board[1][i] && board[1][i] == board[2][i]);
        bool diagonal_match = (board[0][2] == board[1][1] && board[1][1] == board[2][0]) || (board[0][0] == board[1][1] && board[1][1] == board[2][2]);

        if (row_match || column_match || diagonal_match)
        {
            bool x_wins = (row_match && board[i][0] == "X") || (column_match && board[0][i] == "X") || (diagonal_match && board[1][1] == "X")

            if (x_wins) xwins++;
            else owins++;
            return true;
        }
    }

    for (int i = 0; i < 3; i++)//Check for draw
    {
        for (int j = 0; j < 3; j++)
        {
            if (board[i][j] != 'X' && board[i][j] != 'O')
            {
                return false;
            }
        }
    }

    ties++;
    draw = true;
    return true;
}

2）你需要清理电路板。

do
{
    display_board();
    player_turn();
} while (!gameover);
clearboard();

void clearboard()
{
    for (int row = 0; row < 3; row++)
    {
        for (int col = 0; col < 3; col++)
        {
            int val = 3 ** row + col + 1;
            board[row][col] = itoa (val);
        }
    }
}

如果不能解决您的问题，或者我误解了您的问题，请告诉我。

重启程序所以我的C ++游戏是可重放的

3 个答案: