mysql左连接表一到表二由id表，其中表两行最新日期和

Question

我有两张桌子，第一张桌子

+----+-------------------------------------------------+------------+
| id | pixel                                           | date       |
+----+-------------------------------------------------+------------+
|  2 | 7FB30~8BBEA~2B1FB~D5C54~205BD~05A28~9FAB6~F8D2A | 1417334510 |
|  3 | 7FB30~8BBEA~2B1FB~D5C54~205BD~05A28~9FAB6~F8D2A | 1417358993 |
|  4 | 7FB30~8BBEA~2B1FB~D5C54~205BD~05A28~9FAB6~F8D2A | 1417443262 |
+----+-------------------------------------------------+------------+

表二

+----+---------+--------+------------+
| id | lead_id | status | date       |
+----+---------+--------+------------+
| 11 |       3 |      2 | 1417359373 |
| 10 |       2 |      2 | 1417357705 |
| 12 |       2 |      4 | 1417422929 |
| 13 |       4 |      2 | 1417443292 |
+----+---------+--------+------------+

我想在one.id上加入第一至第二表.lead_id和最新日期 如果2.status等于x

，则选择它

所以结果看起来像这样

+--------+--------+-------------+------------+-----------+------------+
| one.id | two.id | two.lead_id | two.status | one.pixel | two.date   |
+--------+--------+-------------+------------+-----------+------------+
|   3    |    11  |     3       |       2    | 7FB30...  | 1417359373 |
|   2    |    12  |     2       |       4    | 7FB30...  | 1417422929 |
|   4    |    13  |     4       |       2    | 7FB30...  | 1417443292 |
+--------+--------+-------------+------------+-----------+------------+

谢谢。

Answer 1

我不确定＆＃34; 2.status等于x＆＃34;与问题或结果有关。看起来你想要表2中或表1之后的第一条记录。

这个想法是使用相关子查询来获取table1中每行的id的行。然后加入其余的字段：

select t.id as one_id, t.two_id, t2.lead_id, t2.status, t.pixel, t2.date
from (select t1.*,
             (select t2.id
              from table2 t2
              where t2.date >= t1.date
              order by date
              limit 1
             ) as two_id
      from table1 t1
     ) t join
     table2 t2
     on t.two_id = t2.id;