Question

我现在要查询两个表，使用左连接，首先使用主表中的按日期分组，日期根据星期分组，现在我也想使用相同的日期分组联接的联接表。如何查询呢？现在我正在这样做

select 
case 
 when order.time BETWEEN '2018-7-27' and '2018-8-3' then '7.27-8.2'
 when order.time BETWEEN '2018-8-3' and '2018-8-10' then '8.3-8.9'
 else "--" end ptime,
 payment.uid, payment.time
 from order  
 left join
 (select uid, time, from payment where create_time between '2018-7-27' and '2018-8-10') payment on payment.uid = order.uid
 where order.time between '2018-7-13' and '2018-8-10'

  +----------+-------+-----------------------+
  |   date   | uid   | time                  |
  +----------+-------+-----------------------+
  | 7.27-8.2 |    42 |   2018-07-27 22:08:22 |  
  | 7.27-8.2 |    42 |   2018-07-27 22:08:22 |              
  | 8.3-8.9  |    50 |   2018-08-04 14:19:00 |         
  | 8.3-8.9  |    50 |   2018-08-04 14:19:00 |      
  | 8.3-8.9  |    76 |   2018-07-28 14:20:00 |       
  | 8.3-8.9  |    76 |   2018-07-28 14:12:00 |         
  | 8.3-8.9  |    76 |   2018-07-28 13:12:00 |          
  | 8.3-8.9  |    88 |   2018-07-28 19:29:00 |       
  | 8.3-8.9  |    98 |   2018-08-09 14:39:00 |           
  +----------+-------+-----------------------+

除了输出：

  +----------+-------+-----+
  |   date   | uid   | time|
  +----------+-------+-----+
  | 7.27-8.2 |    42 |   2 |                
  | 8.3-8.9  |    50 |   2 |         
  | 8.3-8.9  |    76 |   3 |       
  | 8.3-8.9  |    88 |   0 |       
  | 8.3-8.9  |    98 |   1 |        
  +----------+-------+-----+

但是，这样，付款时间不会根据订单日期进行分组。分组规则仍在订单表上。

如何将日期分组应用于两个表，并且对工资表重复数据删除进行相同的分组？非常感谢你！

Answer 1

这是我的解决方案：

select p1.ptime, p2.uid, count(p2.uid) (
select 
case 
when order.time BETWEEN '2018-7-27' and '2018-8-3' then '7.27-8.2'
when order.time BETWEEN '2018-8-3' and '2018-8-10' then '8.3-8.9'
else "--" end ptime
from order  
where order.time between '2018-7-13' and '2018-8-10' group by ptime) p1
left join 
(select 
case 
when payment.time BETWEEN '2018-7-27' and '2018-8-3' then '7.27-8.2'
when payment.time BETWEEN '2018-8-3' and '2018-8-10' then '8.3-8.9'
else "--" end p2time,
count(payment.uid) uid_cnt
from order  
left join
 (select uid, time, from payment where create_time between '2018-7-27' and 
'2018-8-10') payment on payment.uid = order.uid
where order.time between '2018-7-13' and '2018-8-10' group by p2time) p2
on p2.p2time = p1.ptime

Answer 2

您只需要聚合函数count

     select uid,date(ptime) as date,count(payment.time) as time 
  from    
             ( select 
            case 
             when order.time BETWEEN '2018-7-27' and '2018-8-3' then '7.27-8.2'
             when order.time BETWEEN '2018-8-3' and '2018-8-10' then '8.3-8.9'
             else "--" end ptime,
             payment.uid, payment.time
             from order  
             left join
             (select uid, time, from payment where create_time between '2018-7-27' and '2018-8-10') payment on payment.uid = order.uid
             where order.time between '2018-7-13' and '2018-8-10'
            ) as t group by uid,date(ptime)

mysql按日期分组，左连接表按日期分组

2 个答案: