Question

我有两张桌子，第一张桌子

+----------+------------+------+-----+---------+----------------+
| Field    | Type       | Null | Key | Default | Extra          |
+----------+------------+------+-----+---------+----------------+
| id       | int(11)    | NO   | PRI | NULL    | auto_increment |
| pixel    | text       | NO   |     | NULL    |                |
| metadata | text       | NO   |     | NULL    |                |
| data     | text       | NO   |     | NULL    |                |
| attended | int(11)    | NO   |     | NULL    |                |
| alerted  | int(11)    | NO   |     | NULL    |                |
| date     | bigint(20) | NO   |     | NULL    |                |
+----------+------------+------+-----+---------+----------------+

表二

+------------------+------------+------+-----+---------+----------------+
| Field            | Type       | Null | Key | Default | Extra          |
+------------------+------------+------+-----+---------+----------------+
| id               | int(11)    | NO   | PRI | NULL    | auto_increment |
| lead_id          | int(11)    | NO   |     | NULL    |                |
| project_id       | int(11)    | NO   |     | NULL    |                |
| user_id          | int(11)    | NO   |     | NULL    |                |
| type             | int(11)    | NO   |     | NULL    |                |
| status           | int(11)    | NO   |     | NULL    |                |
| text             | text       | NO   |     | NULL    |                |
| comm             | int(11)    | NO   |     | NULL    |                |
| sum              | text       | NO   |     | NULL    |                |
| meeting_date     | text       | NO   |     | NULL    |                |
| meeting_location | text       | NO   |     | NULL    |                |
| date             | bigint(20) | NO   |     | NULL    |                |
+------------------+------------+------+-----+---------+----------------+

我想在1.id = 2.lead_id上连接第一到第二表，其中2.date是最大值如果2.status等于x

，则选择它

我试过，关于一切（接受答案：D），没有得到它。谢谢。这个问题不同它最后有一个AND cluse

Answer 1

SELECT one.*, two.*
FROM one left join two on one.id=two.lead_id 
WHERE MAX(two.date) and two.status='x'

Answer 2

如果您只想将单个值的最小值/最大值作为条件，则可以使用ORDER BY和LIMIT 0,1来获取单行：）

SELECT *
FROM table_one
INNER JOIN (
    SELECT *
    FROM table_two
    WHERE status = XXXXXXXXX
    ORDER BY date DESC
    LIMIT 0,1
) ON table_one.id = lead_id

mysql通过id将表连接表1连接到表2，其中表2为最新日期

2 个答案: