Question

我尝试使用PHPseclib加密和解密一个简单的字符串，但是当我尝试解密它时，结果为null或为空。有人可以帮帮我吗？

这是我的功能

public function myEncrypt($conteudoArquivo, $private_key) {
    $rsa = new Crypt_RSA();
    $rsa->loadKey($private_key);
    $rsa->setEncryptionMode(CRYPT_RSA_ENCRYPTION_PKCS1);    
    $cipherText = base64_encode($rsa->encrypt($conteudoArquivo));
    return $cipherText;
}

public function myDecrypt($cipherText, $public_key) {
    $rsa = new Crypt_RSA();
    $rsa->loadKey($public_key);
    $rsa->setEncryptionMode(CRYPT_RSA_ENCRYPTION_PKCS1);    
    $plainText = base64_decode($rsa->decrypt($cipherText));
    return $plainText;
}

，键值为：

$private_key = "-----BEGIN RSA PRIVATE KEY-----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 
JfhTRRSfi/oOe1aRinfcp/zMJhkf36VA2QJAO8K5JlWJ/Yb1rWGhGaWjINAf7637
E/kxQnTPPZ6Iy9kDcWNVKyub4FblUhoL06Nn4fAd7hZAOzSi4ZHD9XpIQQJAc1MC
QTygcp1jB3A1i0oszLR23FyNVldMoE044BK4cZ5hTm+arRt1MFUPoIj4DNbW3g8O
3uZ1cGf8BA/mc5NDKQJAexm+LcJ3DOTaenQwHw77bfXhbvvCtcvAlYOIawkyDlTx
AkBweqy8BEJbsVRSiBv7k6Hh+T+u1ZWaKDm/ZZCMkA== 
-----END RSA PRIVATE KEY----- ";

$public_key = "-----BEGIN PUBLIC KEY-----
MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQCU+1bLfPmcY7qrF/dTbAtuJlv4R/FVc1WEH9HK
U0jQjX/n/db9vz/x0i3te/bKLNEcwUhBu+PWPnOt/qVURG9BUT6RsCRFUn0CyGiUKoy45o9K/mJA
HmbrNtrUB6ckrYLF75Y50nUNsBVHUDw8yQymmiOBT1gc/KM5s1xTz44LMwIDAQAB
-----END PUBLIC KEY-----";

Answer 1

您需要使用公钥加密并使用私钥解密。这就是非对称加密的工作原理。在RSA＆＃34;加密＆＃34;使用私钥实际上是签名和＆＃34;解密＆＃34;用公钥验证签名。

另一件事是你没有正确反转Base64编码。所以你需要先解码然后解密：

$plainText = $rsa->decrypt(base64_decode($cipherText));

您提供的密钥不能与此代码一起使用，因为它们具有不同的模数。您可以这样生成密钥：

$rsa = new Crypt_RSA();
$rsa->setPrivateKeyFormat(CRYPT_RSA_PRIVATE_FORMAT_PKCS1);
$rsa->setPublicKeyFormat(CRYPT_RSA_PUBLIC_FORMAT_PKCS1);
$keys = $rsa->createKey(2048);
$private_key = $keys["privatekey"];
$public_key = $keys["publickey"];

RSA解密不起作用

1 个答案: