我有以下信息:
这是我的代码:
import java.math.BigInteger;
import java.security.SecureRandom;
public class RSA
{
private final static BigInteger one = new BigInteger("1");
private final static SecureRandom random = new SecureRandom();
// prime numbers
private BigInteger p;
private BigInteger q;
// modulus
private static BigInteger n;
// totient
private static BigInteger t;
// public key
private static BigInteger e;
// private key
private static BigInteger d;
private static String cipherText = "83208298995174604174773590298203639360540024871256126892889661345742403314929861939100492666605647316646576486526217457006376842280869728581726746401583705899941768214138742259689334840735633553053887641847651173776251820293087212885670180367406807406765923638973161375817392737747832762751690104423869019034";
public RSA()
{
p = new BigInteger("9648423029010515676590551740010426534945737639235739800643989352039852507298491399561035009163427050370107570733633350911691280297777160200625281665378483");
q = new BigInteger("11874843837980297032092405848653656852760910154543380907650040190704283358909208578251063047732443992230647903887510065547947313543299303261986053486569407");
n = p.multiply(q);
t = (p.subtract(one)).multiply(q.subtract(one));
e = new BigInteger("65537");
}
public static int generatePrivateKey()
{
d = e.modInverse(t);
return d.intValue();
}
public static String decrypt()
{
String decrypted = "";
int j = 0;
for(int i = 0; i < cipherText.length(); i++){
char c = cipherText.charAt(i);
BigInteger bi1 = BigInteger.valueOf(c);
BigInteger bi2 = bi1.modPow(d, n);
j = bi2.intValue();
c = (char) j;
decrypted += c;
}
return decrypted;
}
public static void main(String[] args) {
RSA rsa = new RSA();
generatePrivateKey();
decrypt();
}
}
当我运行这个解密程序时,我得到的是一个长达309个字符的“?”字符串。为什么,以及如何解决这个问题?