Question

您好我正在学习Java并且正在生成代码，用于将输入的便士数量转换为更改。

所以，如果我输入439p它打印：439p 2 * 200p 4 * 100p 1 * 20p 1 * 10p 1 * 5p 4 * 1p。我需要实现的最后一件事是在打印声明中包括总共有多少硬币

所以在这种情况下它应该打印为：439p 13个硬币2 * 200p 4 * 100p 1 * 20p 1 * 10p 1 * 5p 4 * 1p。我知道这可能很简单，但我真的不知道如何做到这一点，所以任何指导都会受到赞赏：）

我的代码是

class Main { 
public static void main( String args[] ) {

    System.out.print("#Please enter the amount of change : ");
    int change = BIO.getInt();

    while(change > 0)
    {
        int twopounds, pounds, fifty, twenty, ten, five, two, one;

        twopounds = change / 200;
        int left = change % 200;

        pounds = change / 100;
        left = change % 100;

        fifty = left / 50;
        left = left % 50;

        twenty = left / 20;
        left = left % 20;

        ten = left / 10;
        left = left % 10;

        five = left / 5;
        left = left % 5;

        two = left / 2;
        two = left % 2;

        one = left / 1; 

        if (change == 1)
        {
            System.out.print("1 coin");
        }

        if (change > 500)
        { 
            System.out.print("Invalid amount " + change + "p" + "\n");
        }

        if (change <= 500 && change > 1)

            System.out.print(change + "p ");
        {
            if ( twopounds > 0 )
            {
                System.out.print( twopounds > 0 ? twopounds + "*200p " : "" );
            }

            if ( pounds > 0 )
            {
                System.out.print( pounds > 0 ? pounds + "*100p " : "" );
            }

            if ( fifty > 0 )
            {
                System.out.print( fifty > 0 ? fifty + "*50p " : "" );
            }

            if ( twenty > 0 )
            {
                System.out.print( twenty > 0 ? twenty + "*20p " : "" );
            }

            if ( ten > 0 )
            {
                System.out.print( ten > 0 ? ten + "*10p " : "" );
            }

            if ( five > 0 )
            {
                System.out.print( five > 0 ? five + "*5p " : "" );
            }

            if ( two > 0 )
            {
                System.out.print( two > 0 ? two + "*2p " : "" );
            }

            if ( one > 0 )
            {
                System.out.print( one > 0 ? one + "*1p " : "" );
            }
        }
        System.out.print("#Please enter the amount of change : ");
        change = BIO.getInt();
    }

}

Answer 1

简单如下：

int nbCoins = twopounds + pounds + fifty + twenty + ten + five + two + one

Answer 2

声明

pounds = change / 100;
left = change % 100;

应该是

pounds = left / 100;
left = left % 100;

Answer 3

此外，除了unxnut的评论之外，如果你更换

，你可以稍微缩短你的代码。

if ( x > 0 ) {
     System.out.print( x > 0 ? x + "*...p " : "" );
}

的语句

System.out.print( x > 0 ? x + "*...p " : "" );

或

if ( x > 0 ) {
    System.out.print(x + "*...p ");
}

这些条件中的任何一个都足以构成组成变更的零件的条件输出。

如何计算硬币数量？

3 个答案: