请记住,我是Unity的新手。我有2个脚本,我想“梳理”但是当我尝试时它不起作用。
我有一个脚本(Name : RobotController)
。此脚本控制播放器的移动。向上/向下,向下,向左和向右。 (这仅适用于键盘键)
这个脚本工作正常,但现在我想添加手机触摸键的功能。有了这个,我的意思是如果一个人点击“向上箭头”,玩家将跳跃。
向上箭头是一个对象。
这是我得到了我的问题。我用对撞机和脚本创建了向上箭头。
向上箭头脚本:
public class NewJumpScript : MonoBehaviour {
// Use this for initialization
void Start () {
}
// Update is called once per frame
void Update () {
}
void OnMouseOver()
{
if ((Input.touchCount > 0 && Input.GetTouch(0).phase == TouchPhase.Began) || (Input.GetMouseButtonDown(0)))
{
Debug.Log("test");
}
}
}
这是RobotController脚本,带有地面检查等等。
public class RobotController : MonoBehaviour {
//This will be our maximum speed as we will always be multiplying by 1
public float maxSpeed = 2f;
public GameObject player;
public GameObject sprite;
//a boolean value to represent whether we are facing left or not
bool facingLeft = true;
//a value to represent our Animator
Animator anim;
//to check ground and to have a jumpforce we can change in the editor
bool grounded = true;
public Transform groundCheck;
public float groundRadius = 1f;
public LayerMask whatIsGround;
public float jumpForce = 300f;
private bool isOnGround = false;
void OnCollisionEnter2D(Collision2D collision) {
isOnGround = true;
}
void OnCollisionExit2D(Collision2D collision) {
anim.SetBool ("Ground", grounded);
anim.SetFloat ("vSpeed", rigidbody2D.velocity.y);
isOnGround = false;
}
// Use this for initialization
void Start () {
player = GameObject.Find("player");
//set anim to our animator
anim = GetComponent <Animator>();
}
void FixedUpdate () {
//set our vSpeed
//set our grounded bool
grounded = Physics2D.OverlapCircle (groundCheck.position, groundRadius, whatIsGround);
//set ground in our Animator to match grounded
anim.SetBool ("Ground", grounded);
float move = Input.GetAxis ("Horizontal");//Gives us of one if we are moving via the arrow keys
//move our Players rigidbody
rigidbody2D.velocity = new Vector3 (move * maxSpeed, rigidbody2D.velocity.y);
//set our speed
anim.SetFloat ("Speed",Mathf.Abs (move));
//if we are moving left but not facing left flip, and vice versa
if (move > 0 && !facingLeft) {
Flip ();
} else if (move < 0 && facingLeft) {
Flip ();
}
}
void Update(){
if ((isOnGround == true && Input.GetKeyDown (KeyCode.UpArrow)) || (isOnGround == true && Input.GetKeyDown (KeyCode.Space))) {
anim.SetBool("Ground",false);
rigidbody2D.AddForce (new Vector2 (0, jumpForce));
}
if (isOnGround == true && Input.GetKeyDown (KeyCode.DownArrow))
{
gameObject.transform.localScale = new Vector3(transform.localScale.x, 0.2f, 0.2f);
}
if (isOnGround == true && Input.GetKeyUp (KeyCode.DownArrow))
{
gameObject.transform.localScale = new Vector3(transform.localScale.x, 0.3f, 0.3f);
}
}
//flip if needed
void Flip(){
facingLeft = !facingLeft;
Vector3 theScale = transform.localScale;
theScale.x *= -1;
transform.localScale = theScale;
}
}
当需要点击游戏中的“向上箭头”时,该人必须跳到与RobotController脚本中相同的符号。 我希望你理解我的问题。
感谢您的时间和帮助。
答案 0 :(得分:0)
我在两个问题上都给出了相同的答案,因为它们非常相似。您可以根据需要轻松修改代码。
这只是一种方法。可能还有更多,但这是我迄今为止遇到的最好的。
在QUI按钮上,需要这样的脚本:
private Mover playerMover;
void Start()
{
playerMover = GameObject.Find("Character").GetComponent<Mover>();
}
void OnMouseOver()
{
if (Input.GetMouseButton(0))
{
Debug.Log("pressed");
playerMover.MoveButtonPressed();
}
}
请注意,find只在start函数中完成,因为它的计算量很大。
在角色游戏对象上,需要这样的脚本组件:
using UnityEngine;
using System.Collections;
public class Mover : MonoBehaviour {
public void MoveButtonPressed()
{
lastPressedTime = Time.timeSinceLevelLoad;
}
public double moveTime = 0.1;
private double lastPressedTime = 0.0;
void Update()
{
if(lastPressedTime + moveTime > Time.timeSinceLevelLoad)
{
// Character is moving
rigidbody.velocity = new Vector3(1.0f, 0.0f, 0.0f);
}
else
{
rigidbody.velocity = new Vector3(0.0f, 0.0f, 0.0f);
}
}
}