我处理两个CONTACT A,按下并释放屏幕,我如何获得旋转角度?像这场精彩的比赛一样控球。
void Start () {
guiText.text = "Touch the screen.";
AddForce ();
}
// Update is called once per frame
void Update () {
touch = Input.GetTouch (0);
TouchPhase phase = touch.phase;
switch(phase)
{
case TouchPhase.Began:
guiText.text =("New touch detected at position " + touch.position);
a_pos = touch.position;
break;
case TouchPhase.Ended:
guiText.text =("Has cansel by " + touch.position);
b_pos = touch.position;
Calculate();
AddForce ();
break;
}
}
答案 0 :(得分:1)
您可以在滑动结束时从滑动开始创建矢量:
Vector2 swipe = b_pos - a_pos;
如果要查找该矢量和水平轴之间的角度,可以计算:
float angle = Vector2.Angle(Vector.right, swipe);
但是如果您要使用AddForce
的角度,则可以将a_pos
和b_pos
从屏幕坐标转换为世界坐标,并使用这些点为{{{{{{ 1}}:
AddForce