任何人都知道,如果可能的话,如何降低色彩流动的kinect帧分辨率?因为我的范围的全高清尺寸太高了。谢谢 我找到了完整高清帧的代码:
private BitmapSource ToBitmap(ColorFrame frame)
{
int width = frame.FrameDescription.Width;
int height = frame.FrameDescription.Height;
PixelFormat format = PixelFormats.Bgr32;
byte[] pixels = new byte[width * height * ((PixelFormats.Bgr32.BitsPerPixel + 7) / 8)];
if (frame.RawColorImageFormat == ColorImageFormat.Bgra)
{
frame.CopyRawFrameDataToArray(pixels);
}
else
{
frame.CopyConvertedFrameDataToArray(pixels, ColorImageFormat.Bgra);
}
int stride = width * format.BitsPerPixel / 8;
return BitmapSource.Create(width, height, 96, 96, format, null, pixels, stride);
}
答案 0 :(得分:0)
我已经解决了最后添加此代码的问题
BitmapSource bitmap= BitmapSource.Create(width, height, 96, 96, format, null, pixels, stride);
ScaleTransform scale=new ScaleTransform((Width / bitmap.PixelWidth),(Height / bitmap.PixelHeight));
TransformedBitmap tbBitmap = new TransformedBitmap(bitmap, scale);
return tbBitmap;
所以完整的方法是:
private BitmapSource ToBitmap(ColorFrame frame)
{
int width = frame.FrameDescription.Width;
int height = frame.FrameDescription.Height;
PixelFormat format = PixelFormats.Bgr32;
byte[] pixels = new byte[width * height * ((PixelFormats.Bgr32.BitsPerPixel + 7) / 8)];
if (frame.RawColorImageFormat == ColorImageFormat.Bgra)
{
frame.CopyRawFrameDataToArray(pixels);
}
else
{
frame.CopyConvertedFrameDataToArray(pixels, ColorImageFormat.Bgra);
}
int stride = width * format.BitsPerPixel / 8;
BitmapSource bitmap= BitmapSource.Create(width, height, 96, 96, format, null, pixels, stride);
ScaleTransform scale=new ScaleTransform((640.0 / bitmap.PixelWidth),(480.0 / bitmap.PixelHeight));
TransformedBitmap tbBitmap = new TransformedBitmap(bitmap, scale);
return tbBitmap;
}