我的swapData函数基本上在char *
类型的两个节点之间交换数据17 void swapData(struct Node *node1, struct Node *node2)
18 {
19 // Create a new node "temp" that stores the data of node2
20 struct Node *temp = (struct Node *)malloc(sizeof(struct Node));
21 temp->data = malloc(strlen(node2->data));
22
23 strcpy(temp->data,node2->data);
24
25 // Copy data from node1 to node2
26 strcpy(node2->data,node1->data);
27
28 // Copy data from temp to node1
29 strcpy(node1->data,temp->data);
30
31 free(temp->data);
32 free(temp);
33 }
每当我运行valgrind时,它一直给我这个输出:
==27570== Invalid write of size 1
==27570== at 0x4C2C00F: strcpy (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==27570== by 0x400794: swapData (test4.c:23)
==27570== by 0x400A9C: sort (list2.c:20)
==27570== by 0x40086B: main (test4.c:49)
==27570== Address 0x51f11dd is 0 bytes after a block of size 13 alloc'd
==27570== at 0x4C2B6CD: malloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==27570== by 0x40076B: swapData (test4.c:21)
==27570== by 0x400A9C: sort (list2.c:20)
==27570== by 0x40086B: main (test4.c:49)
==27570==
==27570== Source and destination overlap in strcpy(0x51f1130, 0x51f1130)
==27570== at 0x4C2C085: strcpy (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==27570== by 0x4007B2: swapData (test4.c:26)
==27570== by 0x400A9C: sort (list2.c:20)
==27570== by 0x40086B: main (test4.c:49)
==27570==
==27570== Invalid read of size 1
==27570== at 0x4C2C002: strcpy (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==27570== by 0x4007D0: swapData (test4.c:29)
==27570== by 0x400A9C: sort (list2.c:20)
==27570== by 0x40086B: main (test4.c:49)
==27570== Address 0x51f11dd is 0 bytes after a block of size 13 alloc'd
==27570== at 0x4C2B6CD: malloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==27570== by 0x40076B: swapData (test4.c:21)
==27570== by 0x400A9C: sort (list2.c:20)
==27570== by 0x40086B: main (test4.c:49)
==27570==
我认为问题在于swapData中的strcpy。有人能告诉我发生了什么吗?
答案 0 :(得分:12)
你需要为temp-> data
再多一个字节temp->data = malloc(strlen(node2->data)+1);
这是因为您需要存储最后一个字节,然后'\ 0'表示字符串的结尾。
答案 1 :(得分:8)
您不仅需要在malloc长度中添加一个,而且还不能像使用strcpy那样交换字符串。如果第一个字符串用10个字节进行malloced而第二个字符串有29个字节怎么办?复制到swap时,您将超出第一个字符串的缓冲区。交换指针最好。如果将data
定义为固定长度数组,那么您正在做的是正常的,但temp
也可以是相同大小的数组而不是节点。