Question

我正在通过项目euler，我会遇到这个问题。

我要用评论发布我的代码，所以每个人都可以按照我的想法看看我哪里出错了。所有建议都表示赞赏：）

# need to find the largest product in a series

import time # brings time into the code

start = time.time() # creates a start time for the code

list = [] # where I'm going to store the multipules

# the '\ takes the grid and converts it into one long number'

num = '\
73167176531330624919225119674426574742355349194934\
96983520312774506326239578318016984801869478851843\
85861560789112949495459501737958331952853208805511\
12540698747158523863050715693290963295227443043557\
66896648950445244523161731856403098711121722383113\
62229893423380308135336276614282806444486645238749\
30358907296290491560440772390713810515859307960866\
70172427121883998797908792274921901699720888093776\
65727333001053367881220235421809751254540594752243\
52584907711670556013604839586446706324415722155397\
53697817977846174064955149290862569321978468622482\
83972241375657056057490261407972968652414535100474\
82166370484403199890008895243450658541227588666881\
16427171479924442928230863465674813919123162824586\
17866458359124566529476545682848912883142607690042\
24219022671055626321111109370544217506941658960408\
07198403850962455444362981230987879927244284909188\
84580156166097919133875499200524063689912560717606\
05886116467109405077541002256983155200055935729725\
71636269561882670428252483600823257530420752963450' 

i = 0 # start of the ticker

for i in range(0, 1000, 1): # the length of the large block of numbers is 1000

    hold_num = int(num[i])*int(num[i+1])*int(num[i+2]) # im creating a number of every three consecutive numbers ... this is the subset
    list.append(hold_num) # storing the products in a list
    i =+ 1

print max(list) # finding the max of the products in the stored list

我最终收到此错误：

Traceback (most recent call last):
  File "/Users/robertdefilippi/Documents/Python/Euler/8eu.py", line 37, in <module>
    hold_num = int(num[i])*int(num[i+1])*int(num[i+2])
IndexError: string index out of range
[Finished in 0.0s with exit code 1]

关于我做错了什么的任何建议？

Answer 1

当您执行for i in range(0, 1000, 1)时，达到999，num[i+1]和num[i+2]将超出范围。

您必须使用range(0,998,1)。哪个可以缩短为range(998)。执行此操作后，i将会增加并从0开始。您不需要i+=1或i=0。

python中数字子集的产品

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