Question

我的程序的目的是确定一定数量的连续数字的最大乘积。例如，程序提示用户输入一串数字（例如255969406）和连续数字的大小（3），因此我的程序将确定提供的数字中连续3位数的最大乘积，我的程序编译和运行但返回的产品不正确。

def Pro(dig,snum):
    number = 1
    pr = 0
    for x in xrange(0,dig-1):
        pr = int(snum[x])
        number = pr*number
    return number

def Product(dig,indx,snum):
    number = 1
    pr = 0
    for x in xrange(1,dig):

        pr = int(snum[indx+x])
        number = pr*number
    return number


def Main():     
    num = raw_input("Enter a string of digits")
    dig = input("Input number of digits in group")
    x = 1

    val = Pro(dig,num)
    grps = int(len(num)/ dig)
    while x<grps:
        val2= Product(dig,x,num)
        if val2>val:
                val = val2
        x +=1
    print("The max product of " + str(dig) +" consecutive digits in " + num + " is " + str(val))
if __name__ == "__main__":
Main()

Answer 1

你可以尝试一下：

x = '134214257248'

m = 0

for i in range(len(x) - 2):
    m = max(m, int(x[i])*int(x[i+1])*int(x[i+2]))

print m

# 2*5*7 = 70
70

编辑：接受任何数量（n）的连续数字

import numpy as np

x = '134214257248'

m = 0
n = 3

for i in range(len(x) - n + 1):
    m = max(m, np.prod(list(int(l) for l in x[i:i + n])))

print m

70

数字python中连续数字的最大乘积

1 个答案: