Question

在字典中我有Key＆amp;价值如下。我如何获得＆＃34; title＆＃34;来自下面的值并将其存储在NSArray *数据中？

{
    changed = 1414164684;
    city = Stockholm;
    class = "3. Mycket god klass";
    coordinates = "POINT(59.3246206 18.0686084)";
    id = 37510;
    title = "19 Glas Bar & Matsal";
    total = 70;`enter code here`
},
{
    changed = 1413991969;
    city = "G\U00f6teborg";
    class = "2. M\U00e4starklass";
    coordinates = "POINT(57.697944330446234 11.974067687988281)";
    id = 34865;
    title = "28+";
    total = 77;
},

Answer 1

上面提到的代码片段是一个数组，让它命名为＆＃34; result_Array＆＃34;。在＆＃34; result_Array＆＃34;你正在展示两个对象。每个对象都是字典。从每个词典中，您想要获取标题并将其保存在名为＆＃34; data＆＃34;的数组中。我们走了

NSMutableArray *data=[NSMutableArray new];

for(int i=0; i<result_Array.count ; i++)
{
    NSDictionary *dict = [result_Array objectAtIndex:i];
    [data addObject:[dict objectForKey:@"title"]];
}

希望它有所帮助。随意询问任何查询

Answer 2

如果您有一个NSDictionary数组，那么您可以使用方法＆＃34; valueForKey＆＃34;获取密钥的所有值。没有任何迭代：

NSArray *list = @[

@{@"changed":@"1414164684",
@"title":@"19 Glas Bar & Matsal"},

@{@"changed":@"1413991969",
@"title":@"28+"}];

NSArray *titles = [list valueForKey:"title"];

在数组标题中，您只能从列表中获得标题。

Answer 3

您提供的示例代码实际上是一个字典数组。所以用这个小改变回答你的问题

NSArray *originalDict;
NSMutableArray *data = [NSMutableArray new];
for (NSUInteger i = 0; i < originalDict.count; i++) {
    NSDictionary *currentDictionaryPointer = [originalDict objectAtIndex:i];
    NSString *title = [currentDictionaryPointer objectForKey:@"title"];
    [data addObject:title];
 }

其中originalDict是指向您提供的示例代码的对象。

Answer 4

以下示例将使用最少量的代码执行相同操作。

NSMutableArray *arr = [NSMutableArray new];

for (NSDictionary* dict in myArray)
{
    [arr addObject:[dict valueForKey:@"title"]];
}

arr对象将包含键＃39;标题＃39;的所有值。

Answer 5

请执行以下步骤以获得答案

 1.First of all You should Create NSMutableArray
 2.After copy the dictionary to NSMutableArray
    NSMutableArray *array = [yourDictionary copy];
 3.After that set or create the for loop.
 4.Create NSString *strTitle in for loop.
 5.Finally strTitle = [NSString stringWithFormat:@"%@",[[array objectAtIndex:i]valueForKey:@"title"]]];

Answer 6

简单步骤

 NSMutableArray *array = [yourDict copy];[If it is your dict is NSMutableDictionary]
     or
 NSMutableArray *array = [yourDict mutableCopy]; [If it is your dict is NSDictionary];

 for(int i=0;i<[array count];i++)
 {

   NSString *strTitle = [NSString stringWithFormat:@"%@",[[array objectAtIndex:i]valueForKey:@"title"]];
   NSLog(@"the title is==%@",strTitle);

 }

Answer 7

如果你得到“一系列东西”，我不会将它存储在Dict中，我会把它存储到NSArray中，然后迭代它就像：

var myObjects:[Object]

var myCollection = yourJSON as NSArray (assuming that you always get the same.

func myStuff (myCollection) {
    for item in myCollection {
    change = myCollection["changed"] as NSString (assuming a String here)
    city = myCollection["city"] as NSString
    ...
    ...

var Foo:Object = Object()
Foo.change = change
Foo.city = city
...
...


myObjects.append(Foo)
}

稍后，您现在可以轻松地迭代myObjects数组以在TableView中显示内容

如何将NSDictionary值存储到NSArray？

7 个答案: