Question

我有以下简单字典，我想要纬度数组，当状态1存储一个数组，状态2存储第二个数组请帮帮我

 data =     (
            {
        created = "2017-11-13 09:04:18";
        "end_date" = "2017-11-13 11:49:08";
        id = 878;
        latitude = "23.032190322875977000";
        longitude = "72.565238952636720000";
        status = 1;
        "user_id" = 21;
    },
            {
        created = "2017-11-13 11:49:08";
        "end_date" = "2017-11-13 13:13:15";
        id = 888;
        latitude = "23.032133102416992000";
        longitude = "72.565208435058600000";
        status = 1;
        "user_id" = 21;
    },
            {
        created = "2017-11-13 13:13:15";
        "end_date" = "2017-11-13 13:26:26";
        id = 891;
        latitude = "23.032199859619140000";
        longitude = "72.565269470214840000";
        status = 2;
        "user_id" = 21;
    },
            {
        created = "2017-11-13 13:26:26";
        "end_date" = "2017-11-13 16:54:20";
        id = 892;
        latitude = "23.032056808471680000";
        longitude = "72.565223693847660000";
        status = 2;
        "user_id" = 21;
    }

）

Answer 1

使用filter和map：

let statusOne = data.filter({ $0.status == 1 }).map({ $0.latitude })
let statusTwo = data.filter({ $0.status == 2 }).map({ $0.latitude })

Answer 2

请尝试下面的代码：它在swift 3中：

    let lattitude1Array = NSMutableArray()
    let lattitude2Array = NSMutableArray()
    for record in data {
        if let status = record["status"] as? Int {
            if status == 1 {
                lattitude1Array.add(record["lattitude"])
            } else {
                lattitude2Array.add(record["lattitude"])
            }
        }
    }

Answer 3

简单代码使用此

if (isset($_POST['submit1'])) {
  $mediname = pg_escape_string($_POST['medname']);
  $tits = pg_escape_string($_POST['quantity']);

  $quirt = ("UPDATE medicine_invent set med_stock = med_stock - $tits where med_name = $mediname");
  $sq = pg_query($quirt);
}

Answer 4

使用以下代码行

localize=True

希望能帮助你：）

如何从字典中找到价值

4 个答案: