Question

我正在开发一个项目，其中我有一个包含字典的数组在给定的形式中，我必须得到＆＃34; Size_val＆＃34;的值。在＆＃34; size_key＆＃34;。

的基础上

array : (
        {
        "as_per_size" =         {
            lowercatname = abcd;
            sizes =             (
                                {
                    "size_key" = "UP_CHEST";
                    "size_name" = "UP_CHEST";
                    "size_val" = 4;
                    typecat = 1;
                },
                            {
                "size_key" = LENGTH;
                "size_name" = LENGTH;
                "size_val" = 1;
                typecat = 1;
            },
                            {
                "size_key" = DP;
                "size_name" = DP;
                "size_val" = 3;
                typecat = 1;
            },
                            {
                "size_key" = "YOKE_LENGTH";
                "size_name" = "YOKE_LENGTH";
                "size_val" = 2;
                typecat = 1;
            },
                            {
                "size_key" = KNEE;
                "size_name" = KNEE;
                "size_val" = 2;
                typecat = 2;
            },
                            {
                "size_key" = THIGH;
                "size_name" = THIGH;
                "size_val" = 1;
                typecat = 2;
            },
                            {
                "size_key" = CALF;
                "size_name" = CALF;
                "size_val" = 3;
                typecat = 2;
            }
        );
        uppercatname = CHOLI;
    };

我只想获得＆＃34; Size_val＆＃34;的价值。在＆＃34; size_key＆＃34;的基础上。我使用代码获取uppercatname的值。

upstring1 = [[[arrFilteredOrder objectAtIndex:0] objectForKey:@"as_per_size"] objectForKey:@"uppercatname"];
            TypeLabel.text = upstring1;

请给我一些解决方法如何获得此值

Answer 1

请尝试以下编码

NSDictionary *dict = (NSDictionary *)[[[arrFilteredOrder objectAtIndex:0] objectForKey:@"as_per_size"] objectForKey:@"sizes"];

Answer 2

NSArray *arr = [[[[array objectAtIndex:0]objectForKey:@"as_per_size"]objectForKey:@"sizes"]copy];

for(int i=0;i<[arr count];i++)
{
   NSString *strSizekey = [NSString stringWithFormat:@"%@",[[arr objectAtIndex:i]objectForKey:@"size_key"]];
   NSString *strSizeValue = [NSString stringWithFormat:@"%@",[[arr objectAtIndex:i]objectForKey:@"size_val"]];
}

Answer 3

显然你的size值也是一个数组，所以你必须首先得到这个数组，然后循环遍历sizes数组以获得大小字典，并从大小字典中获得你所拥有的size_key的正确size_val。 p>

因此，对于第一个条目和您的尺寸密钥：

NSArray* sizes = [[[arrFilteredOrder[0] objectForKey:@"as_per_size"] objectForKey;@"sizes];

foreach(NSDictionary* sizeDict in sizes {
    NSString* sizeKey = sizeDict[@"size_key];
    if([sizeKey isEqualToString:<your size key>])
    {
            NSString* sizeVal = sizeDict[@"size_val"];
            // now do something with your value
            ...
    }
}

Answer 4

你可以这样：

NSString *sizeValue = nil;

NSArray *sizes = [arrFilteredOrder.firstObject valueForKeyPath:@"as_per_size.sizes"];
for (NSDictionary *size in sizes) {
    if ([size[@"size_key"] isEqualToString:sizeKey]) {
        sizeValue = [size[@"size_val"] description]; //converting to string
    }
}

IOS：如何获取数组内的Dictionary值

4 个答案: