我的代码:
a = [[random.randint(0,10) for i in range(3)] for j in range(4)]
b = [0]*4
c = [random.random() for i in range(12)]
for i in range(len(a)):
for j in a[i]:
b[i] += c[j]
知道如何将其作为列表理解来实现吗?
答案 0 :(得分:3)
使用sum
:
b = [sum(row) for row in a]
b = [sum(c[i] for i in row) for row in a]
答案 1 :(得分:1)
试试这个代码段:
import operator
b = [sum(map(operator.getitem,[c]*3, a_)) for a_ in a]
或operator.itemgetter
:
b = [sum(operator.itemgetter(*_a)(c)) for _a in a]
答案 2 :(得分:0)
对不起,这是你想要的吗?
import random
a = [[random.randint(0,10) for i in range(4)] for j in range(4)]
b = [0 for i in range(4)]
for i in a:
for j in i:
b[a.index(i)] += j
print b