Question

为什么这个功能不能在shell中打印？我不断得到这些东西：

<function terms at 0x025BD3D8>

def gdp_sections ():
    file1 = open("GDP_Section1All_Hist1.csv" , 'r')

    for i in range(7):
        file1.readline()

    a_tuple = []
    line = file1.readline()
    line = line.split(',')
    year = line[22:43]

    line = file1.readline()
    line = line.split(',')
    GDP_Change = line[22:43]

    differences = []

    for i in range (len(year)):
        a_tuple = ((year[i]), (GDP_Change[i]))
        differences.append(a_tuple)



    file1 = open("GDP_Section1All_Hist2.csv" , 'r')
    for i in range(7):
        file1.readline()

    a_tuple = []
    line = file1.readline()
    line = line.split(',')
    year = line[4:48]

    line = file1.readline()
    line = line.split(',')
    GDP_Change = line[4:48]

    for i in range (len(year)):
        a_tuple = ((year[i]), (GDP_Change[i]))
        differences.append(a_tuple)

    print(differences)


def terms():
    file2 = open('the_correct_presidents.txt','r')

    file2.readline()

    for line in range(1,12):
        line = file2.readline()
        line = line.strip().split(',')
        if len(line)>3:
            del line[1]
        name_of_president = line[0]
        term = line[1].split('-')
        year_started_term = int(term[0])
        year_ended_term = int(term[1])
        party = line[2]
        print (line)

Answer 1

你是如何调用terms的？确保包括括号，否则您要求的是名为terms的函数对象，它看起来就像您所看到的那样。函数是Python中的第一类对象，因此可以用作值并打印。

换句话说，你在shell上说这个吗？

>>> print(terms)

当你真的想要这个意思吗？

>>> print(terms())

3.4.1中Python中的函数

1 个答案: