Python 3.4.1 - 嵌套列表中的元素

Question

Numbers = [1, 2, 3, 4, 5]
x_list = list(itertools.combinations(Numbers, 2))
x_list = [(1, 2), (1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5), (3, 4), (3, 5), (4, 5)]

现在，我想创建一个仅包含1，[(1, 2), (1, 3), (1, 4), (1, 5)]的new_list。然后创建仅有两个奇数的new_list2，[(1, 3), (1, 5), (3, 5)]。

我应该怎么做？提前谢谢。

Answer 1

你可以使用列表理解：

>>> [i for i in x_list if 1 in i]  #contain_one
[(1, 2), (1, 3), (1, 4), (1, 5)]


>>> [(k,t) for k,t in x_list if k%2!=0 and t%2!=0] #odd_list
[(1, 3), (1, 5), (3, 5)]

Answer 2

In [2]: x_list = [(1, 2), (1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5), (3, 4), (3, 5), (4, 5)]    

In [3]: one_list = [c for c in x_list if c[0]==1]

In [4]: one_list
Out[4]: [(1, 2), (1, 3), (1, 4), (1, 5)]

In [5]: odd_list = [c for c in x_list if all(i%2==1 for i in c)]

In [6]: odd_list
Out[6]: [(1, 3), (1, 5), (3, 5)]

Answer 3

new_list = [a for a in x_list if 1 in a]
new_list2 = [a for a in x_list if a[0]%2!=0 and a[1]%2!=0]

这应该起作用=）

Answer 4

您可以使用带lambda的过滤器：

Numbers = [1, 2, 3, 4, 5]
x_list = list(combinations(Numbers, 2))
new_list1, new_list2 = list(filter(lambda x: 1 in x, x_list)) ,list(filter(lambda x: x[0] % 2 and x[1] % 2, x_list))

如果模2的任何数字具有余数，则该数字为奇数，x[0]是每个元组中的第一个元素x[1]是第二个。